I think is Y=5x+20
Hope you get it right!
:D
280
The 0 is in the ones.
The 8 is in the tens.
The 2 is in the hundreds.
Answer:
The probability is 
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8,
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function
with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is

35 because if you half the amount of salads he's eaten (seeing as he eats one burger for every two salads) then the extra one is the first salad in the cycle.
Step-by-step explanation:
x²+4x=8
rearrange
x² + 4x - 8 = 0
half of 4 is 2
so
x² + 4x + 2² - 2² - 8 = 0
do x² + 4x + 2²
multiplies to give 4 adds to give 4
2+ 2
(x + 2)²
(x + 2)² - 2² - 8
(x + 2)² - 4 - 8
(x + 2)² - 12
(x + 2 + √12) (x + 2 - √12)
√12 = √4 * √3 = 2 √3
(x + 2 + 2√3) (x + 2 - 2√3)