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nata0808 [166]
3 years ago
12

What is 117.5% as a decimal

Mathematics
1 answer:
trasher [3.6K]3 years ago
8 0
Move the decimal 2 places to the right to get 1.175.
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Simplify each expression:<br> ( 5a^2b^3)(4ab^5)
DIA [1.3K]

Answer:

(22•5a3b4)

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

4ab • (5a2 • b3)

STEP

2

:

Multiplying exponential expressions :

2.1 a1 multiplied by a2 = a(1 + 2) = a3

Multiplying exponential expressions :

2.2 b1 multiplied by b3 = b(1 + 3) = b4

Final result :

(22•5a3b4)

5 0
2 years ago
Read 2 more answers
HELP PLSS I DONT WANNA FAIL
posledela

Answer: 1/2 and 3/6

Explanation: 1/2 is equal to 3/6 because if you divide both 3 and 6 by 2 it’s 1/2

Not sure about 4

3 0
3 years ago
What part of 72 is 12? Without decimals.
Naya [18.7K]
1/6 part of 72 is 12
3 0
3 years ago
Can some please help me?? It’s do today also can you guys explain how to do it because it’s still More questions and I actually
Genrish500 [490]

Answer:

-3

Step-by-step explanation:

Slope of a line is "rise over run".  Pick two points on the line.  For example, (0,4) and (1,1).  As we move from the first point to the second, we move down 3 units and right 1 unit.  So the slope is -3/1 = -3.

Here's an algebraic approach.  If the two points are (x₁, y₁) and (x₂, y₂), then the slope is:

m = (y₂ − y₁) / (x₂ − x₁)

Plugging in our two points:

m = (1 − 4) / (1 − 0)

m = -3

3 0
3 years ago
The length of fencing required for a rectangular garden in terms of its width, x, if it’s length is 2 units more than 1.5 times
JulijaS [17]

Answer:

5x+4 units.

Step-by-step explanation:

Let x be the width of rectangle.

We have been given that the length of garden is 2 units more than 1.5 times it’s width. So length of the rectangle will be: 1.5x+2.

To find the length of total fencing we need to figure out perimeter of rectangle with width x and length 1.5x+2.

Since we know that perimeter of a rectangle is two times the sum of its length and width.

\text{Perimeter of rectangle}=2(\text{Length+Width})

Upon substituting length and width of garden in above formula we will get,

\text{Perimeter of rectangular garden}=2(1.5x+2+x)

\text{Perimeter of rectangular garden}=2(2.5x+2)

Upon using distributive property we will get,

\text{Perimeter of rectangular garden}=2*2.5x+2*2

\text{Perimeter of rectangular garden}=5x+4

Therefore, the length of required fencing will be 5x+4 units.

4 0
4 years ago
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