So I guess we are solving for x here :)
So here is my work...
a=2x+6xz
Basically I think it would be
a=6xz+2x
WAIT WAIT NO I'M WRONG FORGIVE ME!
It's x=a/2(1+3z)
Answer:
3
Step-by-step explanation:
because 3 is a prime number and 3+2=5 which is also a prime number
Answer:
we reject H₀
Step-by-step explanation: Se annex
The test is one tail-test (greater than)
Using α = 0,05 (critical value ) from z- table we get
z(c) = 1,64
And Test hypothesis is:
H₀ Null hypothesis μ = μ₀
Hₐ Alternate hypothesis μ > μ₀
Which we need to compare with z(s) = 2,19 (from problem statement)
The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region
So base on our drawing we will reject H₀
Answer:
Triangles QUT and SVR are congruent because the defining two sides and an included angle of triangles QUT and SVR are equal
Step-by-step explanation:
Here we have QT = SR and
QV = SU
Therefore,
QT = √(UT² + QU²)........(1)
RS = √(VS² + RV²)..........(2)
Since QS = QU + SU = QV + VS ∴ QU = VS
Therefore, since SR = QT and QU = VS, then from (1) and (2), we have UT = RV
Hence since we know all sides of the triangles QUT and SVR are equal and we know that the angle in between two congruent sides of the the triangles QUT and SVR that is the angle in between sides QU and UT for triangle QUT and the angle in between the sides RV and VS in triangle SVR are both equal to 90°, therefore triangles QUT and SVR are congruent.
