For this case we have that the perimeter of the figure is given by the sum of the lengths of the sides, that is:
Thus, the perimeter of the figure is 64 centimeters.
Now, we find the area of the figure:
We have that by definition, the area of a rectangle is given by:
Where:
a and b are the sides of the rectangle
We have 4 vertical rectangles from left to right:
Thus, the total area is
Answer:
The perimeter of the figure is 64 centimeters.
Machine J's equation would be 30x=y. To find out how many more candies Machine J packets, You would plug in 11 as x and you would get 330.
For Machine K, you would just plug in 11 as x. Your answer is 286.
Now you would subtract. 330-286=44.
Range= 4
Range is the highest number minus the lowest number, 10-6=4
Answer:
A) The best way to picture this problem is with a probability tree, with two steps.
The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.
The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.
If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.
If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.
B) So a person can have a red marble and a blue marble in two ways:
1) Picking the red first and the blue last
2) Picking the blue first and the red last
C) P(R&B) = 3/5 = 60%
Step-by-step explanation:
C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5
E. no solution. hope this helps! :)
