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Degger [83]
3 years ago
13

What is the mixed number for 51/9

Mathematics
2 answers:
Setler79 [48]3 years ago
6 0

5 2/3 is the answer to your question
olga_2 [115]3 years ago
5 0
Ok, if you are looking for the mixed number, you just divide the numerator, 51, by the denominator, 9. If you divide 51 by 9, you should get 5, because 9 times 5 equals 45, with  6 remainder. So the mixed number will be 5 6/9.

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16 out of the 50 digital video recorders
IceJOKER [234]

Answer:

34

Step-by-step explanation:

6 0
3 years ago
A survey on healthy choices was given to gym members at Work It Out. The results
irina [24]

Answer:

The correct option is 4) 0.72.

Step-by-step explanation:

Consider the provided information.

Let us consider that there are 100 members.

(Note: you can take any number the answer will remain the same.)

90% of its members drank protein shakes and of the members who drank  protein shakes.

90% of 100 is 90.

Thus, 90 members drank protein shake.

Of the members who drank   protein shakes, 30% took weight-loss medication.

30% of 90 is 27.

That means 27 out of 90 took weight loss medication.

Out of 100 members 90 drank protein shakes that means 10 members does not take protein shakes.

Only 10% of members  who did not drink protein shakes took weight-loss medication.

10% of 10 is 1, that means 1 member out of 10 took weight loss medication.

Thus the required table is:

                                        Medication   Not Medication      Total

Drank shakes                       27                   63                      90

Doesn't Drank shakes          1                      9                        10

Total                                      28                   72                     100

Now we need to find the probability that a gym member does not take weight-loss medication.

72 out of 100 members does not take weight-loss medication.

Therefore, the required probability is: \frac{72}{100}=0.72

Hence, the correct option is 4) 0.72.

5 0
3 years ago
Find a statement that is equivalent to the absolute value inequality
IceJOKER [234]

<u>Answer</u>:

Option 5: -4 ≤ 7x - 7 ≤ 4

<u>Step-by-step explanation:</u>

It is required to find which expression is equivalent to |7x-7| ≤ 4

So, at the beginning we should review the rules of absolute value inequalities.

1) If |x| ≤ a ⇒ -a ≤ x ≤ a

2) If |x| < a ⇒ -a < x < a

3) If |x| ≥ a ⇒ x ≤ -a or x  ≥  a

4) If |x| > a ⇒ x < -a or x  >  a

Applying the first rule to the given absolute value inequality:

|7x-7| ≤ 4  ⇒  -4 ≤ 7x-7 ≤ 4

So, the answer is option 5

7 0
3 years ago
Order 0.0509km , 60.5 m and 5700cm​
krok68 [10]

Answer:  0.0509km 60.5m 5700cm

Greatest to least

Step-by-step explanation:

3 0
2 years ago
A simple random sample of 28 Lego sets is obtained and the number of pieces in each set was counted.The sample has a standard de
Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

Given that:

A simple random sample n = 28

sample standard deviation S = 12.65

standard deviation \sigma = 11.53

Level of significance ∝ = 0.05

The objective is to test the claim that the number of pieces in a set has a standard deviation different from 11.53.

The null hypothesis and the alternative hypothesis can be computed as follows:

Null hypothesis:

H_0: \sigma^2 = \sigma_0^2

Alternative hypothesis:

H_1: \sigma^2 \neq \sigma_0^2

The test statistics can be determined by using the following formula in order to test if the claim is statistically significant or not.

X_0^2 = \dfrac{(n-1)S^2}{\sigma_0^2}

X_0^2 = \dfrac{(28-1)(12.65)^2}{(11.53)^2}

X_0^2 = \dfrac{(27)(160.0225)}{132.9409}

X_0^2 = \dfrac{4320.6075}{132.9409}

X_0^2 = 32.5002125

X^2_{1- \alpha/2 , df} = X^2_{1- 0.05/2 , n-1}

X^2_{1- \alpha/2 , df} = X^2_{1- 0.025 , 28-1}

From the chi-square probabilities table at 0.975 and degree of freedom 27;

X^2_{0.975 , 27} = 14.573

X^2_{\alpha/2 , df} = X^2_{ 0.05/2 , n-1}

X^2_{\alpha/2 , df} = X^2_{0.025 , 28-1}

From the chi-square probabilities table at 0.975 and degree of freedom 27;

X^2_{0.025 , 27}= 43.195

Decision Rule: To reject the null hypothesis if X^2_0  \ >  \ X^2_{\alpha/2 , df}  \ \  \ or \ \ \   X^2_0 \  < \  X^2_{1- \alpha/2 , df} ; otherwise , do not reject the null hypothesis:

The rejection region is X^2_0  \ >  43.195 \ \  \ or \ \ \   X^2_0 \  < \  14.573

Conclusion:

We fail to reject the null hypothesis since  test statistic value 32.5002125  lies  between 14.573 and 43.195.

6 0
3 years ago
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