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3 years ago

11

I don't inderstand how would i graph and find the range and domain

1 answer:

lisov135 [29]3 years ago

8 0

To find the domain and range is very simple. The domain will always be the input values or x values. For example ( 3,0) the domain is 3 being the x value. The range is the output value or y value and in the example (3,0) the range is 0. Hope this helps :)

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Solving equations with variables on both sides <br><br><br> 7+9x=6x-2

katrin2010 [14]

Answer:

Here

Step-by-step explanation:

We move all terms to the left:

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We get rid of parentheses

9x-6x+2+7=0

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3x+9=0

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3 years ago

Sarah ran 1/3 of a mile 5 days in a row. How many miles did she run in total?

Vladimir79 [104]

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2 years ago

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year. If you had purchased a h

Kipish [7]

Answer:

The home would be worth $249000 during the year of 2012.

Step-by-step explanation:

The price of the home in t years after 2004 can be modeled by the following equation:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the price of the house in 2004 and r is the growth rate.

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.

This means that $r = 0.047$

$172000 in 2004

This means that $P(0) = 172000$

What year would the home be worth $ 249000 ?

t years after 2004.

t is found when P(t) = 249000. So

$P(t) = P(0)(1+r)^{t}$

$249000 = 172000(1.047)^{t}$

$(1.047)^{t} = \frac{249000}{172000}$

$\log{(1.047)^{t}} = \log{\frac{249000}{172000}}$

$t\log(1.047) = \log{\frac{249000}{172000}}$

$t = \frac{\log{\frac{249000}{172000}}}{\log(1.047)}$

$t = 8.05$

2004 + 8.05 = 2012

The home would be worth $249000 during the year of 2012.

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3 years ago