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Grace [21]
3 years ago
13

3n - 7 > n + 1 or 4n - 5 < 3n - 3

Mathematics
1 answer:
hodyreva [135]3 years ago
8 0

Answer:

n > 4

Step-by-step explanation:

3n - 7 > <u>n</u> + 1

Move variable to the left side and change its sign

3n <u>- </u><u>n</u> - 7 > 1

...

3n <u>- </u><u>7</u> > n + 1

Move constant to the right side and change its sign

3n - n > 1 <u>+ </u><u>7</u>

...

<u>3</u><u>n - n</u> > 1 + 7

Collect the like terms

<u>2</u><u>n</u> < 1 + 7

...

3n - n > <u>1</u><u> + </u><u>7</u>

Add the numbers

2n < <u>8</u>

Divide both sides of the inequality by 2

Solution:

<u>n </u><u>></u><u> </u><u>4</u><u> </u> Answer:

n < 2

Step-by-step explanation:

4n - 5 < <u>3n</u> - 3

Move variable to the left side and change its sign

4n <u>- 3n</u> - 5 < - 3

...

4n <u>- 5</u> < 3n -3

Move constant to the right side and change its sign

4n - 3n < - 3 <u>+ 5</u>

...

<u>4n - 3n</u> < - 3 + 5

Collect the like terms

<u>n</u> < - 3 + 5

...

4n - 3n < <u>- 3 + 5</u>

Calculate the sum

n < <u>2</u>

...

Solution:

<u>n < 2</u>

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