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3 years ago

3n - 7 > n + 1 or 4n - 5 < 3n - 3

Mathematics

1 answer:

hodyreva [135]3 years ago

8 0

Answer:

n > 4

Step-by-step explanation:

3n - 7 > n + 1

Move variable to the left side and change its sign

3n - n - 7 > 1

...

3n - 7 > n + 1

Move constant to the right side and change its sign

3n - n > 1 + 7

...

3n - n > 1 + 7

Collect the like terms

2n < 1 + 7

...

3n - n > 1 + 7

Add the numbers

2n < 8

Divide both sides of the inequality by 2

Solution:

n > 4  Answer:

n < 2

Step-by-step explanation:

4n - 5 < 3n - 3

Move variable to the left side and change its sign

4n - 3n - 5 < - 3

...

4n - 5 < 3n -3

Move constant to the right side and change its sign

4n - 3n < - 3 + 5

...

4n - 3n < - 3 + 5

Collect the like terms

n < - 3 + 5

...

4n - 3n < - 3 + 5

Calculate the sum

n < 2

...

Solution:

n < 2

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$\large\boxed{x = -2}$

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