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2 years ago

If X and Y are 2 finite sets such that n() = 9, n( XY) - 4 and n( XY) -15, then n() is

Mathematics

1 answer:

Artist 52 [7]2 years ago

8 0

Answer:

I think it's a hope this helps

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Which linear Function has the greatest Y intercept

Svetlanka [38]

Answer:

:pog_champ:

Step-by-step explanation:

7 0

3 years ago

A taxi service charges an initial fee plus $1.80 per mile. How far can you travel for 14$

BigorU [14]

14 / 1.8 = 7.77777778

about 7.77777778 miles

but it depends on what the initail fee is

3 0

3 years ago

Plot the points - 5.5 and 3.5 on the number line. Then use the number line to show and find the distance between the two points.

Mkey [24]

0.5+1+1+1+1+1+1+1+1+0.5=9

5 0

3 years ago

Sofia takes 10mg of a medicine whose concentration in blood decreases by a factor of one half every day. Let t be the number of

bazaltina [42]

Answer: Medication in Lexi's system on day t becomes,

$L=10.625(\frac{1}{2})^{t-4}$

Step-by-step explanation:

Since we have given that

Initial amount Sofia takes of a medicine = 10 mg

Concentration in blood decreases by a factor of one half every day.

So, it becomes,

$S=10(\frac{1}{2})^t\\\\here,\text{ t denotes number of days}$

According to question, four days later, it becomes,

$S=10(\frac{1}{2})^4\\\\S=\frac{10}{16}\\\\S=0.625\ mg$

We have given that Lexi takes 10 mg of the same medicine.

So, it becomes,

$10+0.625\\\\10.625\ mg$

Hence, Medication in Lexi's system on day t becomes,

$L=10.625(\frac{1}{2})^{t-4}$

3 0

3 years ago

Read 2 more answers

Every day a kindergarten class chooses randomly one of the 50 state flags to hang on the wall, without regard to previous choice

Svet_ta [14]

Answer:

a.) P(x = X) = $\frac{1}{50}$

b.) $\frac{1}{50} \times\frac{1}{50} \times\frac{1}{50} = \frac{1}{125000}$

c.) 0.00118

Step-by-step explanation:

The sample space Ω = flags of all 50 states

a.) Any one of the flags is randomly chosen. Therefore we can write the

probability measure as P(x = X) = $\frac{1}{50}$ , for all the elements of the sample

space, that is for all x ∈ Ω.

b.) the probability that the class hangs Wisconsin's flag on Monday,

Michigan's flag on Tuesday, and California's flag on Wednesday

= $\frac{1}{50} \times\frac{1}{50} \times\frac{1}{50} = \frac{1}{125000}$

c.) the probability that Wisconsin's flag will be hung at least two of the three days

= Probability that Wisconsin's flag will be hung on two days + Probability that Wisconsin's flag will be hung on three days

= P(x = 2) + P(x = 3)

= $(\binom{3}{2}\times \frac{1}{50} \times \frac{1}{50}\times \frac{49}{50}) + (\binom{3}{3}\times \frac{1}{50} \times \frac{1}{50}\times \frac{1}{50})\\$

= $\frac{147}{125000} + \frac{1}{125000}$

= $\frac{148}{125000}$

= 0.00118

7 0

2 years ago