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inna [77]
3 years ago
6

maximize P=9x+9y Subject to 2x+y is less than or equal to 30 x+2y is less than or equal to 24 x, y is greater than 0 What is the

maximum value of P? (integer or fraction)
Mathematics
1 answer:
Inga [223]3 years ago
3 0
Find the intersection point between the 2 restraint equations:
30 - 2x = 12 - \frac{1}{2} x  \\ \frac{3}{2} x = 18  \\  x = 12

Substitute back in to find y-value:
y = 30 - 2(12) = 6

P is maximized at point (12,6)
P = 9(12)+9(6) = 162
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Answer:

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Step-by-step explanation:

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3 years ago
One bar of candy A and two bars of candy B have 774 calories. Two bars of candy A and one bar of candy B contains 786 calories.
vampirchik [111]
◆ Define the variables:

Let the calorie content of Candy A = a
and the calorie content of Candy B = b

◆ Form the equations:

One bar of candy A and two bars of candy B have 774 calories. Thus:

a + 2b = 774

Two bars of candy A and one bar of candy B contains 786 calories

2a + b = 786

◆ Solve the equations:

From first equation,
a + 2b = 774
=> a = 774 - 2b

Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
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◆ Find caloric content:

Caloric content of candy B = 254 calorie

Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
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3 years ago
Sami cut 6 and three fourth inches off a long roll of paper if the row 36 and one third inches long how long was the original ro
cestrela7 [59]

Answer:

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Step-by-step explanation:

The computation of the length of the original roll of papers is shown below:

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Now convert the above fractions into a number

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And,

6 3 ÷4 = 27 ÷ 4

Now add these two numbers i.e.

109 ÷3  + 27 ÷ 4

= 436 + 81 ÷ 12

= 517 ÷12

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3 years ago
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kari74 [83]

Answer: .84

Step-by-step explanation:

5 0
3 years ago
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