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Trava [24]
2 years ago
14

Negative six multiplied by negative ten is subtracted from eight multiplied by five. Find the number

Mathematics
2 answers:
My name is Ann [436]2 years ago
7 0

Answer:

The answer is -20.

Step-by-step explanation:

(8 × 5) - (-6 × -10)

= 40 - 60

= -20

Alenkasestr [34]2 years ago
5 0
So first we can find -6 times -10. Since there are two negatives, the answer will be positive. -6 times -10 =60. Then we need to find 8 times 5. 8 times 5 is 40.
Now we have 40-60=-20.
The answer is -20
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David's last equation to solve is x/100+3/100=8/100. Write and solve an equivalent equation with easier numbers that would give
JulijaS [17]
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sertanlavr [38]

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5 0
3 years ago
In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A
vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

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As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

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The standard deviation will be:

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We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

\mu=np=300*0.932=279.6

The standard deviation will be:

\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

P(270\leq x\leq280)=P(269.5

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

P(X=280)=P(279.5

8 0
3 years ago
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