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2 years ago

Negative six multiplied by negative ten is subtracted from eight multiplied by five. Find the number

Mathematics

2 answers:

My name is Ann [436]2 years ago

7 0

Answer:

The answer is -20.

Step-by-step explanation:

(8 × 5) - (-6 × -10)

= 40 - 60

= -20

Alenkasestr [34]2 years ago

5 0

So first we can find -6 times -10. Since there are two negatives, the answer will be positive. -6 times -10 =60. Then we need to find 8 times 5. 8 times 5 is 40.
Now we have 40-60=-20.
The answer is -20

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2 years ago

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3 years ago

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vredina [299]

Answer:

c) P(270≤x≤280)=0.572

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Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

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As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

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We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

$z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932$

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

$\mu=np=300*0.932=279.6$

The standard deviation will be:

$\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36$

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

$P(270\leq x\leq280)=P(269.5$

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

$P(X=280)=P(279.5$

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2 years ago