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Charra [1.4K]
3 years ago
5

The theater has 7 rows of 8 chairs. For an upcoming show the theater needs to have 5 times more chairs. They are able to add 3 m

ore chairs to each row and can add as many rows as they need. How many total rows would be required?
Mathematics
2 answers:
Effectus [21]3 years ago
7 0

Answer:

number 1 is 56 number 2 is 28

Step-by-step explanation:

it said it

777dan777 [17]3 years ago
6 0

Answer:

26 rows

Step-by-step explanation

Since each row as 8 chairs and they can add 3 chairs to each row,

the rows can now have 11 chairs in them.

they needed 5x as many chairs as 8x7. this equals 280 chairs (8x7=56--> 56x 5 = 280) 280 divided by 11 chairs per row is 25.48 which is 26 rows with some empty chairs left over, therefore your answer is 26 rows.

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11
lorasvet [3.4K]

Answer:

//

Step-by-step explanation:

Bill's answer is wrong because timesing 150 by 1.3 is increasing the number by 30%, not 3%

If he wanted to use this method, he would have ti times 150 by 1.03

3 0
3 years ago
Read 2 more answers
Show how you did it
tankabanditka [31]

Answer:

7 3/5

Step-by-step explanation:

6 \times \frac{8}{5}  =  \frac{38}{5} = 7 \times \frac{3}{5}

4 0
4 years ago
Y=6x4 + 7x2 and x = vw +1
belka [17]

Answer:

w=-1/6 or w=-3

Step-by-step explanation:

Substitute the value of x and y into the first equation and solve for w:

y=6x^4+7x^2\\10=6(\sqrt{w+1})^4+7(\sqrt{w+1})^2\\10=6(w+1)^2+7(w+1)\\10=6(w^2+2w+1)+7w+7\\10=6w^2+12w+6+7w+7\\0=6w^2+19w+3

Solve for w with the quadratic formula:

w=\frac{-b\±\sqrt{b^2-4ac}}{2a} \\w=\frac{-19\±\sqrt{19^2-4(6)(3)} }{2(6)}\\w=\frac{-19\±\sqrt{361-72}}{12} \\w=\frac{-19\±\sqrt{289} }{12} \\w=\frac{-19\±17}{12}

After simplifying, we get either w=-1/6 or w=-3.

Not sure if w needs to satisfy all conditions while maintaining everything as real numbers, because if w=-3, then x is an imaginary number. But both values work just as fine.

4 0
2 years ago
20 is what percent of 100
Gemiola [76]
20 would be 20% of 100.

Just like 67.67 would be 67.67% of 100.

:)
6 0
3 years ago
Read 2 more answers
A quiz consists of 20 multiple-choice questions find mean and standard deviation
worty [1.4K]

Since the problem is quite vague because the number of choice per question is not written here. I’ll just put for 4 choices and 5 choices each.

To compute for the 5 choices each:

Mean = np = 20 (1/5) = 4

Standard deviation = sqrt(npq) = sqrt (4*(4/5) = 1.79

 

To compute for the 4 choices each:

Mean = np = 20 (1/4) = 5

Standard deviation = sqrt(npq) = sqrt (5*(4/5) = 2

4 0
3 years ago
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