Answer:
Criteria for my Cup:
I want my cup to be short and wide.
Step-by-step explanation:
a) By the way, a cup can be measured in volume. There are no tall and skinny cups. They are not attributes of a cup. However, a cup can be short (height). It can also be wide, usually measured in diameter and radius.
b) Data:
Volume cubic centimeters milliliters fluid ounces cups
cold pack 150 150 5 0.6
drink compartment 600 600 20 2.5
total 750 750 25 3.1
Hello :
f(x) = sin²(x) +cos(x)
the dirivate is : f'(x) = 2sin(x) cos(x) -sin(x) because :
( sin²(x) )' = 2sin(x) cos(x) and (cos(x))' = - sin(x)
f'(x) = 0 : sin(x) (2cos(x) - 1) = 0
sin(x) = 0 : x = k <span>π k in Z
</span>2cos(x) - 1 =0 : 2cos(x) =1
cos(x) = 1/2 = cos( π /3)
x = π /3 +2k π or x = - π /3 +2k π
in intervall : <span> <span>[0
, 2π] :
k=0 : x= 0 f(0) = 1 ( </span></span>minimum<span>)
</span>k=1 : x = π f(π) = -1 (<span>minimum)
x= </span> π /3 f ( π /3 ) = 1.25 ( <span>maximum)</span>
Answer:
a) 1/64
b) 1/4096
Step-by-step explanation:
As you can tell from the example, the exponent of 1/2 is the number of heads in a row.
a) p(6 heads in a row) = (1/2)^6 = 1/(2^6) = 1/64
b) p(12 heads in a row) = (1/2)^12 = 1/(2^12) = 1/4096
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<em>Additional comment</em>
The probability of a head is 1/2 because we generally are concerned with a "fair coin." That is defined as a coin in which each of the 2 possible outcomes has the same probability, 1/2. Similarly, a "fair number cube" has 6 faces, and the probability of each is defined to be the same as any other, 1/6. Loaded dice and unfair coins do sometimes show up in probability problems.
Well, the last digit in the product will only come from the last digits of the numbers that you're multiplying together. So for 0.303 & 4.48, that last digits are 3 & 8 so that last digit in the product would come from
So 4. There are only two options that end in 4, 1.35744 & 0.13574. You can by the magnitude of the numbers that it isn't as small as 0.13574 so the answer must be 1.35744.
