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2 years ago

5

Every time a customer purchases a new computer, one month later they receive a survey in the mail. Eighty-five percent of the su

rveys stated that the customer had no technical issues. The people that return the survey are considered...

1 answer:

True [87]2 years ago

4 0

Answer:

Respondents

Step-by-step explanation:

The customers that buy a new computer and receive a survey in the mail about the performance of the computer after one month are called respondents.

They are called respondents because they took part in a survey or poll about the performance of the computer they bought a month ago. Statistically, not everyone that got the mail took part in the poll, those ones are called non respondents, while the ones that took part in the survey are known as respondents.

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5y-4x=-7 what does x equal

harkovskaia [24]

Answer:

$x = \frac{5y + 7}{4}$

Step-by-step explanation:

5y - 4x = - 7

5y - 4x + 4x = - 7 + 4x [adding + 4x on both sides ]

5y + 7 = - 7 + 7 + 4x [adding 7 on both sides , - 4x + 4x = 0 ]

5y + 7 = 4x [ -7 + 7 = 0 ]

$\frac{5y + 7}{4} = \frac{4x}{4}$ [ dividing by 4 on both sides ]

$x = \frac{5y + 7}{4}$

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2 years ago

Subtracting a number is the same as adding its opposite.

statuscvo [17]

Answer:

in first question, answer is 12

in second question, answer is -12

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2 years ago

How to Write twenty-four hundredths as a simplified fraction.

Andrews [41]

Answer:

24/100

=6/25

Step-by-step explanation:

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2 years ago

Problems 2.21, 2.22, 2.23

RoseWind [281]

Statements can be proved by contrapositive, contradiction or by induction.

<em>2.21 and 2.23 are proved by contrapositive</em>
<em>2.22 is proved by induction</em>

<u />

<u />

<u>2.21: If </u> $n^3$ <u> is even, then n is even (By contrapositive)</u>

The contrapositive of the above statement is that:

<em>If n is odd, then </em> $n^3$ <em> is odd</em>

Represent the value of n as:

$n = 2k + 1$ , where $k \ge 0$

Take the cube of both sides

$n^3 = (2k + 1)^3$

Expand

$n^3 = 8k^3 + 6k^2 + 6k + 1$

Group

$n^3 =[ 8k^3 + 6k^2 + 6k] + 1$

Factor out 2

$n^3 =2[4k^3 + 3k^2 + 3k] + 1$

Assume w is an integer; where:

$w =4k^3 + 3k^2 + 3k$

So, we have:

$n^3 =2w + 1$

The constant term (i.e. 1) means that $n^3$ is odd.

Hence, the statement has been proved by contrapositive.

<em>i.e. If n is odd, then </em> $n^3$ <em> is odd</em>

<u />

<u>2.22 </u> $3n + 4$ <u> is even, if and only if n is even</u>

We have: $3n + 4$ <u />

<u />

Assume that: $n = 2k + 2$ for $k \ge 0$

So, we have:

$3n + 4 = 3(2k + 2) + 4$

Open bracket

$3n + 4 = 6k + 6 + 4$

$3n + 4 = 6k + 10$

Factorize

$3n + 4 = 2(3k + 5)$

The factor of 2 means that $3n + 4$ is even.

<em>Hence, </em> $3n + 4$ <em> is even, if and only if n is even </em>

<em />

<u />

<u>2.22: </u> $s \ne -1$ <u> and </u> $t \ne -1$ <u>, then </u> $s + t + st \ne -1$ <u />

To do this, we prove by contrapositive.

The contrapositive of the above statement is:

If $s = -1$ and $t=-1$ , then $s + t + st = -1$

We have:

$s + t + st = -1$

Substitute the values of s and t in: $s + t + st = -1$

$-1 -1 -1 \times -1 = -1$

$-1 -1 + 1 = -1$

$-1 = -1$

Hence, by contrapositive:

If $s = -1$ and $t=-1$ , then $s + t + st = -1$

Read more about proofs at:

brainly.com/question/19643658

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3 years ago

4x+11y=7<br><br>4x+3y=-1<br>what are the steps

andreev551 [17]

Answer:

x = -1, y = 1

Step-by-step explanation:

Given that:

$\begin{bmatrix}4x+11y=7\\ 4x+3y=-1\end{bmatrix}$

Isolate x for 4x + 11y = 7 which ⇒ $x=\frac{7-11y}{4}$

Substitute $x=\frac{7-11y}{4}$ into the equation: which is:

$\begin{bmatrix}4\cdot \frac{7-11y}{4}+3y=-1\end{bmatrix}$

Drop Down to:

$\begin{bmatrix}7-8y=-1\end{bmatrix}$

Isolate y for 7-8y = -1: y = 1

Thus, $x=\frac{7-11y}{4}$

Substitute y = 1

Hence,

$x=\frac{7-11\cdot \:1}{4}=-1$

Solution ⇒ x = -1 and y = 1

<u><em>~learn with lenvy~</em></u>

6 0

1 year ago

Read 2 more answers