Answer:
A) g(t) = - 16*t² + 80*t
B) domain is ( 0 ≤ t ≤ 5 )
Step-by-step explanation:
A) for the model rocket
h = 0 and v = 80 feet/sec
Then the equation g(t) = -16*t² + v*t + h
became
g(t) = - 16*t² + 80*t + 0 g(t) = - 16*t² + 80*t
B) The equation g(t) = - 16*t² + 80*t is defined for all real numbers then the domain interval for t is ( -∞ , ∞ ). Now in our case, a model rocket was launched is not possible to get negative values for g(t) then the biggest value for t = 5 from
-16*t² + 80*t ≥ 0
-16*t ≥ -80 16*t ≤ 80
t ≤ 5
And the domain is ( 0 ≤ t ≤ 5 )
<u>Answer:</u>
Solving for x in 12x − 39 ≤ 9 and −4x + 3 < −6 we get 2.25 < x ≤ 4
<u>Solution</u>:
Need to find the value of x which satisfies following two given expressions
12x − 39 ≤ 9 ------(1)
−4x + 3 < −6 ------ (2)
Lets first solve expression (1)
12x − 39 ≤ 9
Adding 39 on both sides , we get
12x−39 + 39 ≤ 9 +39
=>12x ≤ 48
=> x ≤ 48/12
=> x ≤ 4
Now solving expression (2)
−4x+3<−6
=> -4x < -6 – 3
=> -4x < -9
=> 4x > 9
=> x > 9/4
=> x > 2.25
So from solution of expression (1) and (2) , we get x ≤ 4 and x > 2.25
Hence required value of x is 2.25 < x ≤ 4.
Answer:
110 is the answer because 10 tens equal 100 and 10 ones equal 10
Step-by-step explanation:
Answer: pretty sure it will be .5
