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3 years ago

What is the volume of the rectangular prism if the length is 5 mm, the width is 2 mm, and the height is 2 mm?

Mathematics

2 answers:

Len [333]3 years ago

7 0

Answer is d) 20 cubic millimeters and I showed working in the pic

olasank [31]3 years ago

3 0

The volume of a rectangular prism is Length x width x height

l = 5 mm
w = 2 mm
h = 2mm
volume = 5x2x2 = 20 cubic millimeters

answer is D

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Please help anyone know how to do this.

dexar [7]

sides of right angle triangle follows Pythagoras theorem

a^2 + b^2 = c^2

where a, b and c are sides of triangle

if you check, option 3 follow this. so answer is option 3

6 0

3 years ago

Read 2 more answers

Find x: 3/(x-4)(x-7) + 6/(x-7)(x-13) + 15/(x-13)(x-28) - 1/x-28 = -1/20

Novay_Z [31]

The value of x<em> </em>in the polynomial fraction 3/((x-4)•(x-7)) + 6/((x-7)•(x-13)) + 15/((x-13)•(x-28)) - 1/(x-28) = -1/20 is <em>x </em>= 24

<h3>How can the polynomial with fractions be simplified to find<em> </em><em>x</em>?</h3>

The given equation is presented as follows;

$\frac{3}{(x - 4) \cdot (x - 7) } + \frac{6}{(x - 7) \cdot (x - 13) } + +\frac{15}{(x - 13) \cdot (x - 28) } - \frac{1}{(x - 28) } = - \frac{1}{20}$

Factoring the common denominator, we have;

$\frac{3\cdot(x - 13) \cdot(x - 28) + 6 \cdot(x - 4) \cdot(x - 28) + 15 \cdot(x - 4) \cdot(x - 7) - (x - 4) \cdot (x - 7)\cdot(x - 13)}{(x - 4) \cdot (x - 7)\cdot(x - 13) \cdot(x - 28)} + = - \frac{1}{20}$

Simplifying the numerator of the right hand side using a graphing calculator, we get;

By expanding and collecting, the terms of the numerator gives;

-(x³ - 48•x + 651•x - 2548)

Given that the terms of the numerator have several factors in common, we get;

-(x³ - 48•x + 651•x - 2548) = -(x-7)•(x-28)•(x-13)

Which gives;

$\frac{-(x - 7) \cdot(x - 28)\cdot (x - 13)}{(x - 4) \cdot (x - 7)\cdot(x - 13) \cdot(x - 28)} + = - \frac{1}{20}$

Which gives;

$\frac{-1}{(x - 4)} + = - \frac{1}{20}$

x - 4 = 20

Therefore;

x = 20 + 4 = 24

Learn more about polynomials with fractions here:

brainly.com/question/12262414

#SPJ1

5 0

2 years ago

Solve the quadratic equations

Alexxx [7]

Answer:

for quadratic equation 1

y^2-10y+21=0

Step-by-step explanation:

y^2-7y-3y+21=0

y(y-7)-3(y-7)=0

(y-7)(y-3)=0

y-7=0,y-3=0

y=7,y=3

y=(3,7)

for quadratic equation 2

16p^2-8p+1=0

16p^2-4p-4p+1=0

4p(4p-1)-1(4p-1)=0

(4p-1)twice=0

4p-1=0,4p-1=0

4p=1

p=1/4 twice

for quadratic equation 3

x^2-400=0

x^2=400

x=√400

x=20

for quadratic equation 4

-16m^2-8m-1=0

multiply the equation by -

16m^2+8m+1=0

16m^2+4m+4m+1=0

4m(4m+1)1(4m+1)=0

4m+1=0 twice

m=-1/4 twice

for quadratic equation 5

-3n^2+75=0

divide both side by -3

-3n^2/-3=-75/-3

n^2=25

n=√25

n=5

6 0

2 years ago

Para cambiar 212% a fracción debemos dividirlo entre 100% ?

kirza4 [7]

Si tiene que divide 212/100=53/25

4 0

3 years ago

(45pts) An elevator holds at most 1,400 pounds. A team of movers and their cart have a combined weight of 1,200 pounds. If each

emmainna [20.7K]

Let $x$ be the number of boxes the team brings with them. Their weight combined with the boxes can't exceed the capacity of 1400. Assuming the elevator runs fine at that exact weight, you want to find the number of boxes, each of which contributes 40 pounds. This is given by the equation

$1400=1200+40x$

Solving for $x$ , you have

$1400=1200-40x$
$200=40x$
$x=5$

So the team can bring *at most* 5 boxes at a time.

4 0

3 years ago