All categories

3 years ago

What is the volume of the rectangular prism if the length is 5 mm, the width is 2 mm, and the height is 2 mm?

Mathematics

2 answers:

Len [333]3 years ago

7 0

Answer is d) 20 cubic millimeters and I showed working in the pic

olasank [31]3 years ago

3 0

The volume of a rectangular prism is Length x width x height

l = 5 mm
w = 2 mm
h = 2mm
volume = 5x2x2 = 20 cubic millimeters

answer is D

You might be interested in

What 2 numbers multiply to -216 and add up to 6

Lena [83]

-12 and 18

hope this helps :)

7 0

3 years ago

Read 2 more answers

Select the correct answer from each drop-down menu. Complete the statement. The solutions of sin2x= √3/2

alex41 [277]

Answer:

henc X = 30°

Step-by-step explanation:

here is the proof

when X=30° then

sin2x = sin2×30

=sin 60°

= √3/2

or else,

putting value of X = 30° then

sin2x= 2sinxcosx

= 2×sin30°×cos30°

=2×1/2×√3/2

= 2√3/4

= √3/2

hence proved sin2x= √3/2.

7 0

3 years ago

Benjamin has to wear a uniform to school. His uniform is made up of tan or blue pants and a blue or white collared shirt. Benjam

oee [108]

Explanation:

As his uniform is made up of tan or blue pants and a blue or white collared shirt.

So, there are possibly four combinations which are as follows:

tan pants/blue shirt
tan pants/white shirt
blue pants/blue shirt
blue pants/white shirt

As Benjamin carries an extra piece of white shirt. So, he has a little bit better than 25% chance of wearing his favorite combination.

So,

Probability of getting tan pants = 2/4 = 1/2
Probability of getting white shirt = 3/5

The probability of getting both can be computed by simply multiplying 2/4 and 3/5.

So,

Probability of getting both = 1/2 × 3/5 = 3/10 ⇒ 30%

Keywords: probability, chance

Learn more about from /brainly.com/question/14382310

#learnwithBrainly

3 0

3 years ago

How to calculate this question?

Degger [83]

Answer:

if you use perimeter area you can get answer

8 0

3 years ago

A swimming pool with a volume of 30,000 liters originally contains water that is 0.01% chlorine (i.e. it contains 0.1 mL of chlo

SpyIntel [72]

Answer:

$R_{in}=0.2\dfrac{mL}{min}$

$C(t)=\dfrac{A(t)}{30000}$

$R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}$

$A(t)=300+2700e^{-\dfrac{t}{1500}},$ A(0)=3000$

Step-by-step explanation:

The volume of the swimming pool = 30,000 liters

(a) Amount of chlorine initially in the tank.

It originally contains water that is 0.01% chlorine.

0.01% of 30000=3000 mL of chlorine per liter

A(0)= 3000 mL of chlorine per liter

(b) Rate at which the chlorine is entering the pool.

City water containing 0.001%(0.01 mL of chlorine per liter) chlorine is pumped into the pool at a rate of 20 liters/min.

$R_{in}=$ (concentration of chlorine in inflow)(input rate of the water)

$=(0.01\dfrac{mL}{liter}) (20\dfrac{liter}{min})\\R_{in}=0.2\dfrac{mL}{min}$

Volume of the pool =30,000 Liter

$Concentration, C(t)= \dfrac{Amount}{Volume}\\C(t)=\dfrac{A(t)}{30000}$

(d) Rate at which the chlorine is leaving the pool

$R_{out}=$ (concentration of chlorine in outflow)(output rate of the water)

$= (\dfrac{A(t)}{30000})(20\dfrac{liter}{min})\\R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}$

(e) Differential equation representing the rate at which the amount of sugar in the tank is changing at time t.

$\dfrac{dA}{dt}=R_{in}-R_{out}\\\dfrac{dA}{dt}=0.2- \dfrac{A(t)}{1500}$

We then solve the resulting differential equation by separation of variables.

$\dfrac{dA}{dt}+\dfrac{A}{1500}=0.2\\$The integrating factor: e^{\int \frac{1}{1500}dt} =e^{\frac{t}{1500}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{1500}}+\dfrac{A}{1500}e^{\frac{t}{1500}}=0.2e^{\frac{t}{1500}}\\(Ae^{\frac{t}{1500}})'=0.2e^{\frac{t}{1500}}$

Taking the integral of both sides

$\int(Ae^{\frac{t}{1500}})'=\int 0.2e^{\frac{t}{1500}} dt\\Ae^{\frac{t}{1500}}=0.2*1500e^{\frac{t}{1500}}+C, $(C a constant of integration)\\Ae^{\frac{t}{1500}}=300e^{\frac{t}{1500}}+C\\$Divide all through by e^{\frac{t}{1500}}\\A(t)=300+Ce^{-\frac{t}{1500}}$

Recall that when t=0, A(t)=3000 (our initial condition)

$3000=300+Ce^{0}\\C=2700\\$Therefore:\\A(t)=300+2700e^{-\dfrac{t}{1500}}$

3 0

3 years ago