Let A be some subset of a universal set U. The "complement of A" is the set of elements in U that do not belong to A.
For example, if U is the set of all integers {..., -2, -1, 0, 1, 2, ...} and A is the set of all positive integers {1, 2, 3, ...}, then the complement of A is the set {..., -2, -1, 0}.
Notice that the union of A and its complement make up the universal set U.
In this case,
U = {1, 2, 3, 6, 10, 13, 14, 16, 17}
The set {3, 10, 16} is a subset of U, since all three of its elements belong to U.
Then the complement of this set is all the elements of U that aren't in this set:
{1, 2, 6, 13, 14, 17}
Answer:
Step-by-step explanation:
<u>Take some reference points on the graph of f and g:</u>
- f(2) = 1, g(2) = 2
- f(4) = 2, g(4) = 4
- f(8) = 4, g(8) = 8
<u>According to the numbers above we can state:</u>
So the value of k is 2
The <em><u>correct answer</u></em> is:
$72.31 – $24.61 – $16.49; $31.21
Explanation:
We know we end the month with $72.31.
We made two deposits during the month and no other activity. This means if we take the amounts of the deposits away from the total at the end of the month, we can find how much we had at the beginning of the month:
72.31-24.61-16.49 = 31.21
we know that
surface area of the cylinder=2*{area of the base}+perimeter of base*height
area of the base=pi*r²
r=40 ft
Area of base=pi*40²
Area of the base=1600*pi ft²
Perimeter of the base=2*pi*r
Perimeter of the base=2*pi*40
Perimeter of the base=80*pi ft
surface area of the cylinder=2*1600*pi+80*pi*17
surface area=4560*pi ft²
therefore
the answer is the option
4560π ft2
