Find the solution of this system of equations. Separate the x- and y-values with a comma. x - 4y = 12 and x - y = 0

1 answer:

6 0

Use elimination and subtitution method to solve the problem.
First, eliminate x and you'll find the value of y
x - 4y = 12
x - y = 0
--------------- - (substract)
-3y = 12
y = 12/-3
y = -4

Second, subtitute -4 as y and you'll find the value of x
x - y = 0
x- (-4) = 0
x + 4 = 0
x = -4

The solution
x,y = -4,-4

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Answer:

$\pmb{ \pink{QUESTION�}}$

Find the midsegment of the triangle which is parallel to CA.

$\pmb{ \pink{ANSWER:-}}$

Tip

A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.

$\frak{Explanation:-}$

We have to find the segment which is parallel to CA.

From the given data,

The segment EG is the midsegment of the triangle $\triangle$ ABC.

So we have,

A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.

$\implies\rm{midsegment \: EG \: parallel \: to \: CA}$