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eduard
3 years ago
7

​Artificial turf is being used to cover a playing field. If the field is rectangular with a length of a yd and 110 yd width of 8

5 yd, how much artificial turf must be purchased to cover the field?
Mathematics
1 answer:
larisa86 [58]3 years ago
8 0

Answer:

9350 yd² artificial turf must be purchased to cover the field.

Step-by-step explanation:

Given information: Shape of the playing field is rectangular.

Length of the field = 110 yd

Width of the field = 85 yd

Area of a rectangle is

Area=Length \times Width

Substitute length=110 and width=85 in the above formula, to find the area of the field.

Area=110 \times 85

Area=9350

The area of field is 9350 yd². Therefore, 9350 yd² artificial turf must be purchased to cover the field.

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(6,3) -> (-3/2x , 2/3y) -> (x + 6 , y - 4) -> (2/3x , -3/2y)
Oliga [24]

Answer:

Please refer to the attached image.

4 0
3 years ago
The dimensions of the tank are 50 cm by 32 cm by 20 cm. The tank is full of water and sand. The ratio of the volume of water to
Sauron [17]

Given:

Dimensions of a tank are 50 cm by 32 cm by 20 cm

The tank is full of water and sand

Ratio of volume of water to the volume of sand is 5:1

To find:

Volume of water in the tank in liters

Solution:

Without loss of generality, let,

Length of tank = 50 cm

Breadth of tank = 32 cm

Height of tank = 20 cm

Then, we have,

Total Volume of the tank = Length * Breadth * Height

\Rightarrow Total Volume = 50*32*20 cc

\Rightarrow Total Volume = 32000 cc

It is given that,

Volume of water : Volume of sand = 5:1

\Rightarrow (Volume of water)/(Volume of sand) = 5/1

Cross multiplying, we have,

Volume of sand = (Volume of water)/5

It is also given that the tank is full of water and sand. This implies that,

Volume of water + Volume of sand = Total Volume

Using the value, we obtained, we get,

Volume of water + (Volume of water)/5 = Total Volume

\Rightarrow (6 * Volume of water)/5 = Total Volume

Plugging in the value of total volume, we get,

\Rightarrow (6 * Volume of water)/5 = 32000 cc

\Rightarrow Volume of water = \frac{32000*5}{6} cc

\Rightarrow Volume of water \approx 26,666.6667 cc

We know that,

1 cc = 0.001 liters

\Rightarrow 26,666.6667 cc = (26666.6667 * 0.001) liters

\Rightarrow 26,666.6667 cc \approx 26.667 liters

Thus, Volume of water in the tank is approximately 26.667 liters

Final Answer:

Volume of water in the tank (in liters) is approximately 26.667 liters

4 0
2 years ago
Alright this time can somebody help? ​
Deffense [45]

I'm pretty sure the answer is 232cm

11x8=88

88÷2=44

44x4=176

8x7= 56

176+56=232

Correct me if I'm wrong :)

6 0
2 years ago
Read 2 more answers
Need help with my Geometry, can someone help me with 4,5 and 10?
xz_007 [3.2K]
For questions 4 and 5, use laws of complementary and supplementary angles to find values of x. I'm not too sure about what question 10 is asking.

Hope I helped :)

6 0
3 years ago
Read 2 more answers
Family has an annual income of ​$23 comma 400. Of​ this, one fourth
denis23 [38]

Amount spent for food = $5850, housing = $4680, clothing = $2340, savings = $2600, taxes = $5850, expenses = $2080.

<u>Step-by-step explanation:</u>

Step 1:

Given details are Total Income = $23,400

Step 2:

Amount spent for food, F= 1/4th of 23,400 = 1/4 \times 23400

= $5850

Step 3:

Amount spent for housing, H = 1/5th of 23,400 = 1/5 \times23400

= $4680

Step 4:

Amount spent for clothing, C = 1/10th of 23,400 = 1/10 \times 23400 = $2340

Step 5:

Amount spent for savings, S = 1/9th of 13,400 = 1/9\times 23400 = $2600

Step 6:

Amount spent for taxes, T = 1/4th of 23,400 =  1/4 \times 23400 =$5850

Step 7:

Find amount spent on other expenses by totaling all expenditures and subtracting from the annual income.

Annual Income = F + H + C + S + T + E

Amount spent on other expenses, E = 23400 - (5850 + 4680 + 2340 + 2600 + 5850)

E = 23400 - 21320

E = $2080

5 0
3 years ago
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