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notsponge [240]
2 years ago
5

The product of s and 10

Mathematics
2 answers:
aniked [119]2 years ago
5 0

Answer:

The product of s and 10 = 10s

Step-by-step explanation:

The term “product” determines a multipaction problem.

The variable S is unknown within the value

so with a numerical and a algebraic number, the number comes together

ad-work [718]2 years ago
3 0

Answer:

10s

Step-by-step explanation:

The <u>product</u> of s and 10

In mathematic, when the word "product" is used, it means multiplication.

10 × s ---> 10s *Both of them are the same.*

Hope this helps and stay safe, happy, and healthy, thank you :) !!

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A salesperson works 40 hours per week at a job where he has two options for being paid. Option A is an hourly wage of ​$28. Opti
irina [24]

Answer:

$9500

Step-by-step explanation:

Given, Option A: Hourly wage is $19 and the salesperson works 40 hours per week. So, he will earn in a week= 19 X 40 = $760

Now, according to option b, he will get 8% commission on weekly sales.

Let. x = the amount of weekly sales.

To earn the same amount of option A, he will have to equal the 8% of x to $760

So, 8x/100= 760

Or, 8x= 76000

Or, x= 76000/8= 9,500

the salesman needs to make a weekly sales of $9,500 to earn the same amount with two options.

8 0
3 years ago
Read 2 more answers
|14+x|-5=k solve for k​
guajiro [1.7K]

Answer:

k=|14+x|-5

Step-by-step explanation:

just rewrite the equation as k=|14+x|-5

6 0
3 years ago
Ryan wants to rent a limo for a trip to the city. The limo costs $700 for the night and $2.50 per mile. What is the greatest dis
Pavel [41]

Answer:

20 miles

Step-by-step explanation:

the answer is 20 miles

5 0
3 years ago
Read 2 more answers
I think I know this much so far for A (but I could be wrong):
Eduardwww [97]
Part A. You have the correct first and second derivative.

---------------------------------------------------------------------

Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.

-------------------------------------------------------------

Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out

To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h  ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0. 
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well. 
6 0
3 years ago
Are the graphs of 2x-4y=-12 and y=2x+1 parallel, perpendicular, or neither?
Sauron [17]

Answer:

I believe the answer is neither

Step-by-step explanation:

4 0
2 years ago
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