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qaws [65]
3 years ago
9

Consider the following set of equations:

Mathematics
1 answer:
alina1380 [7]3 years ago
3 0
B. x+4=3x+6 ..........
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Find the value of x.
podryga [215]

Answer:

x=17

Step-by-step explanation:

the two segements equal each other, so make teh equations equal eachother and solve for x ,2x-10=x+7



4 0
4 years ago
A share of stock in the bree medical supply company is quoted at 35 1/4,suppose you hold 20 shares of that stock which you bough
kodGreya [7K]
Hi there, we know the total number of stocks bough is 20, the rate was 31 1/2=63/2, 20*63/2=10*63=630 dollars, the rate they were sold is 35 1/4=141/4 dollars, 5*141=705 dollars, the amount of profit is 20 stocks. So, 705-630=75 dollars. So, the answer is C. You made a profit of $75.00
5 0
4 years ago
Read 2 more answers
if a car travels at a speed of 25 mi/h for t hours, then travels 45mi/h for m hours, what does the expression 25t+45mi represent
Ratling [72]
V = s/t ⇒ s = vt

25 mi/h · th + 45 mi/h · mh = 25mi · t + 45mi · m = (25t + 45m)mi

Answer: The expression represent <span>the distance that <span>car traveled.</span></span>
7 0
3 years ago
Read 2 more answers
Find the length of AB
AleksandrR [38]

Answer:

6.4

Step-by-step explanation:

A(3, 9)

B(8, 5)

\sqrt{(3-8)^{2} +(9-5)^{2} }

8 0
3 years ago
What is the equation of the parabola?
irina1246 [14]

Because the parabola opens down and the vertex is at (0, 5), we conclude that the correct option is:

y  = -(1/8)*x² + 5.

<h3>Which is the equation of the parabola?</h3>

The relevant information is that we have the vertex at (0, 5), and that the parabola opens downwards.

Remember that the parabola only opens downwards if the leading coefficient is negative. Then we can discard the two middle options.

Now, because the parabola has the point (0, 5), we know that when we evaluate the parabola in x = 0, we should get y = 5.

Then the constant term must be 5.

So the correct option is the first one:

y  = -(1/8)*x² + 5.

If you want to learn more about parabolas:

brainly.com/question/4061870

#SPJ1

3 0
2 years ago
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