3 years ago

Consider the following set of equations:

Mathematics

1 answer:

alina1380 [7]3 years ago

3 0

B. x+4=3x+6 ..........

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Please help number 5 thank you

Triss [41]

Answer 2,290 of total sheets of paper she bought.

Step-by-step explanation:

65x36=2340

subtract 50 for the black pages that she did not use.

2340-50=2,290

6 0

2 years ago

Read 2 more answers

Someone Please help me

Cerrena [4.2K]

Answer:

y= -2x+4

Step-by-step explanation:

To find the slope find 2 points and use "rise/run", that will get -2

To find the y-intercept look at where the line crosses the y-axis. that will be 4

so -2x+4

5 0

2 years ago

Let V be the volume of the solid obtained by rotating about the y-axis the region bounded y = 4x and y = x2/4 . Find V by slicin

aliya0001 [1]

Answer:

Step-by-step explanation:

Consider the graphs of the $y = 4x$ and $y = \frac{x^{2} }{4}$ .

By equating the expressions, the intersection points of the graphs can be found and in this way delimit the area that will rotate around the Y axis.

$4x = \frac{x^{2} }{4} \\ x^{2} = 16x \\ x^{2} - 16x = 0 \\ x(x-16) = 0$ then $x=0$ o $x=16$ . Therefore the integration limits are:

$y = 4(0) = 0$ and $y = 4(16) = 64$

The inverse functions are given by:

$x = 2 \sqrt{y}$ and $x = \frac{y}{4}$ . Then

The volume of the solid of revolution is given by:

$\int\limits^{64}_ {0} \, [2\sqrt{y} - \frac{y}{4}]^{2} dy = \int\limits^{64}_ {0} \, [4y - y^{3/2} + \frac{y^{2}}{16} ]\ dy = [2y^{2} - \frac{2}{5}y^{5/2} + \frac{y^{3}}{48} ]\limits^{64}_ {0} = 546.133 u^{2}$

6 0

3 years ago

Calculate the area of triangle ABC with altitude AD, given A(-5, 4), B(-6, 1), C(0, 1), and D(-5, 1).

snow_lady [41]

Answer:

the area of triangle ABC = 9

Step-by-step explanation:

Check the photo below for the details.

3 0

3 years ago

Find the area of triangle ABC with the given parts.<br> 3) A = 38.8°<br> b= 13.9 in.<br> c=7.3 in.

tamaranim1 [39]

The area of triangle ABC with the given parts is c- 7.3in

5 0

2 years ago