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3 years ago

7/8 divided by 11/12 Answer has to be a fraction. Include steps if possible.

2 answers:

7 0

7/8 / 11/12. First get the reciprocal of 11/12 (which is 12/11). Then multiply by the reciprocal. 7/8 * 12/11 = 84/88 don't forget to simplify 21/22

solong [7]3 years ago

3 0

7/8 time the reciprocal of 11/12 would be 12/11
7/8 times 12/11
7 times 12 is 84 and 11 times 8 is 88
so ur fraction is 84/88
simplify 21/22

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LiRa [457]

Answer:

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Step-by-step explanation:

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3 years ago

A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]

= [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0

2 years ago

Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 76.676.6

faltersainse [42]

Answer:

Step-by-step explanation:

Researchers measured the data speeds for a particular smartphone carrier at 50 airports.

The highest speed measured was 76.6 Mbps.

n= 50

X[bar]= 17.95

S= 23.39

a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?

If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps

b. How many standard deviations is that [the difference found in part (a)]?

To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation

Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations

c. Convert the carrier's highest data speed to a z score.

The value is X= 76.6

Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51

d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?

The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.

I hope it helps!

3 0

3 years ago

Which of these people will be eligible for a tax deduction?

AfilCa [17]

Miles, who makes cash contributions to charities.

6 0

2 years ago

Read 2 more answers

Could someone answer these 3 for me?

KengaRu [80]

Answer:

x=4.77

Angle 3=98.32 degrees

Angle 6= 81.68 degrees

Step-by-step explanation:

(Assuming these are parallel lines), Angle 3 and angle 5 are equal because they are alternate Angles. Therefore we can write the following equation to solves for x:

16x+22=3x+84 (angle 3=angle5)

Which we can now solve:

16x +22 - 22 - 3x=3x-3x+84-22

13x=62

13x/13=62/13

x=4.77 (2dp)

We can then use this x to calculate angle 3:

16(4.77)+22

76.33+22=98.32 degrees

Finally,

Angle 6 and angle 3 are interior angles, so they add up to 180 degrees.

So to find angle 6,we can just subtract angle 3 from 180:

180-98.32=81.68 degrees.

Hope this helped!

6 0

3 years ago