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oksian1 [2.3K]
3 years ago
15

Please help ASAP thank you

Mathematics
1 answer:
krek1111 [17]3 years ago
3 0

Answer:

-4

Step-by-step explanation:

First find 2 points (look at graph)

(0,2) and (2,-6)

= \frac{-6-2}{2-0}

= \frac{-8}{2}

= -4

Slope is -4

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it takes a lady 26 minutes to travel 3 km by walking the first part at 6 km per hour and running the second part at 10 km per ho
Natasha2012 [34]

Answer:

78 meter 360meters 600 meters

3 0
3 years ago
A helicopter is flying above a town. the local high school is directly to the east of the helicopter at a 20° angle of depressio
guapka [62]
Answer: 4.5 miles

Explanation:

When you draw the situation you find two triangles.

1) Triangle to the east of the helicopter

a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°

b) hypotensue = distance between the high school and the helicopter

c) opposite-leg to angle 20° = heigth of the helicopter

d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x

2) triangle to the west of the helicopter

a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°

b)  distance between the helicopter and the elementary school = hypotenuse

c) opposite-leg to angle 62° = height of the helicopter

d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x

3) tangent ratios

a) triangle with the helicpoter and the high school

tan 20° = Height / x ⇒ height = x tan 20°

b) triangle with the helicopter and the elementary school

tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°

c) equal the height from both triangles:

x tan 20° = (5 - x) tan 62°

x tan 20° = 5 tan 62° - x tan 62°

x tan 20° + x tan 62° = 5 tan 62°

x  (tan 20° + tan 62°) = 5 tan 62°

⇒ x = 5 tant 62° / ( tan 20° + tan 62°)

⇒ x = 4,19 miles

=> height = x tan 20° = 4,19 tan 20° = 1,525 miles

4) Calculate the hypotenuse of this triangle:

hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²

hipotenuse = 4.46 miles

Rounded to the nearest tenth = 4.5 miles

That is the distance between the helicopter and the high school.
5 0
3 years ago
Read 2 more answers
Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio
JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

Initial =1\ million

6\ years\ later = 500,000

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

\frac{dA}{dt} = kA

Where k represents the constant of proportionality

\frac{dA}{dt} = kA

Multiply both sides by dt/A

\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}

\frac{dA}{A}  = k\ dt

Integrate both sides

\int\ {\frac{dA}{A}  = \int\ {k\ dt}

ln\ A = kt + lnC

Make A, the subject

A = Ce^{kt}

t = 0\ when\ A =1\ million i.e. At initial

So, we have:

A = Ce^{kt}

1000000 = Ce^{k*0}

1000000 = Ce^{0}

1000000 = C*1

1000000 = C

C =1000000

Substitute C =1000000 in A = Ce^{kt}

A = 1000000e^{kt}

To solve for k;

6\ years\ later = 500,000

i.e.

t = 6\ A = 500000

So:

500000= 1000000e^{k*6}

Divide both sides by 1000000

0.5= e^{k*6}

Take natural logarithm (ln) of both sides

ln(0.5) = ln(e^{k*6})

ln(0.5) = k*6

Solve for k

k = \frac{ln(0.5)}{6}

k = \frac{-0.693}{6}

k = -0.1155

Recall that:

\frac{dA}{dt} = kA

Where

\frac{dA}{dt} = Rate

So, when

A = 600000

The rate is:

\frac{dA}{dt} = -0.1155 * 600000

\frac{dA}{dt} = -69300

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0
3 years ago
3. Classify each function according to whether it is a vertical stretch, a vertical compression, a horizontal
Vladimir79 [104]

The classifications of the functions are

  • A vertical stretch --- p(x) = 4f(x)
  • A vertical compression --- g(x) = 0.65f(x)
  • A horizontal stretch --- k(x) = f(0.5x)
  • A horizontal compression  --- h(x) = f(14x)

<h3>How to classify each function accordingly?</h3>

The categories of the functions are given as

  • A vertical stretch
  • A vertical compression
  • A horizontal stretch
  • A horizontal compression

The general rules of the above definitions are:

  • A vertical stretch --- g(x) = a f(x) if |a| > 1
  • A vertical compression --- g(x) = a f(x) if 0 < |a| < 1
  • A horizontal stretch --- g(x) = f(bx) if 0 < |b| < 1
  • A horizontal compression  --- g(x) = f(bx) if |b| > 1

Using the above rules and highlights, we have the classifications of the functions to be

  • A vertical stretch --- p(x) = 4f(x)
  • A vertical compression --- g(x) = 0.65f(x)
  • A horizontal stretch --- k(x) = f(0.5x)
  • A horizontal compression  --- h(x) = f(14x)

Read more about transformation at

brainly.com/question/1548871

#SPJ1

4 0
2 years ago
Show the relationship between the number of miles and the number of hours in the ratio 12 to 1
densk [106]

Answer:

The person has a speed of 12 miles per hour.

Step-by-step explanation:

The ratio is 12 miles to 1 hour.

This means, that in every hour, the person can move 12 miles and has a speed of 12 miles per hour.

3 0
3 years ago
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