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3 years ago

I need to solve these systems using substitution.

Mathematics

1 answer:

Georgia [21]3 years ago

8 0

y is some number and it is equal to -4x+2

y being that same number is also equal to x-3

therefore, we can equate -4x+2 and x-3 to get x-3 = -4x+2

This is the same as starting with y = -4x+2 and replacing the y with x-3

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Let's solve for x

x-3 = -4x+2

x-3+4x = -4x+2+4x .... add 4x to both sides

5x-3 = 2

5x-3+3 = 2+3 .... add 3 to both sides

5x = 5

5x/5 = 5/5 .... divide both sides by 5

x = 1

With this x value, you can now find the y value. Pick any equation that has x and y in it. If we picked the first equation, then

y = -4x+2

y = -4*1+2 ... plug in x = 1

y = -4+2

y = -2

Or we can pick the second equation

y = x-3

y = 1-3 .... plug in x = 1

y = -2

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<h3>The solution to the system is (x,y) = (1, -2)</h3>

Graphing the two lines will have them intersect at this location.

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A package contains 12 resistors, 3 of which are defective. If 4 are selected, find the probability of getting

s344n2d4d5 [400]

Answer:

Incomplete question, but I gave a primer on the hypergeometric distribution, which is used to solve this question, so just the formula has to be applied to find the desired probabilities.

Step-by-step explanation:

The resistors are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

12 resistors, which means that $N = 12$

3 defective, which means that $k = 3$

4 are selected, which means that $n = 4$

To find an specific probability, that is, of x defectives:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = x) = h(x,12,4,3) = \frac{C_{3,x}*C_{9,4-x}}{C_{12,4}}$

7 0

3 years ago

What is −13+2z=−56 Thanks

Zinaida [17]

<h3>Original Equation:</h3>

$-\frac{1}{3}+2z=-\frac{5}{6}$

<h3>Steps:</h3>

<em>*To solve for a variable, isolate the desired variable onto one side.</em>

Firstly, we want to add 1/3 to each side however -5/6 and 1/3 do not share the same denominator, and we want them to have that and we can do that by finding the LCD, or lowest common denominator. To find the LCD, list the multiples of 6 and 3 and the lowest multiple that they share is their LCD. In this case, their LCD is 6. Multiply -1/3 by 2/2:

$-\frac{1}{3}\times \frac{2}{2}=-\frac{2}{6}\\\\-\frac{2}{6}+2z=-\frac{5}{6}$

Now that we have common denominators, add both sides by 2/6:

$2z=-\frac{3}{6}\\\\2z=-\frac{1}{2}$

Next, you want to cancel out 2 to isolate z. Usually, one would divide both sides by 2, however remember that <u>dividing by a number is the same as multiplying by it's reciprocal.</u> To find a number's reciprocal, flip the numerator and denominator around. In this case, since 2 is a <em>whole number</em> this means that the denominator is 1. In this case: 2/1 would become 1/2. Multiply both sides by 1/2:

$\frac{1}{2}\times 2z= -\frac{1}{2}\times \frac{1}{2}\\\\z=-\frac{1}{4}$

<h3>Final Answer:</h3>

<u>Your final answer is z = -1/4.</u>

7 0

3 years ago

Which is the least expensive per oz? 12 oz for $5.28 or 18 oz for $7.96. round to the nearest cent?

blondinia [14]

5.28 / 12 = 0.44 per oz
7.96 / 18 = 0.4422 rounds to 0.44 per oz

technically, by rounding to the nearest cent, they are the same cost.

6 0

3 years ago

Read 2 more answers

Anyone? Pleasee help

xeze [42]

Answer:

Angle 1 = 128

Angle 2 = 52

Angle 3 = 68

Angle 4 = 60

Angle 5 = 124

Step-by-step explanation:

Had to use supplementary theorem, vertical angles theorem, and that the angles of a triangle add up to 180.

I hope this helps!

8 0

3 years ago

The left and right page numbers on an

liubo4ka [24]

The pages would be 166 and 167

7 0

4 years ago