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3 years ago

Here is a tree diagram showing the sample space for two independent events. How many outcomes are there for the second event?

Mathematics

2 answers:

Ierofanga [76]3 years ago

8 0

I am pretty sure it is 8

iVinArrow [24]3 years ago

5 0

I think your answer would be 8 hope this help

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What is the slope of the graph

denpristay [2]

Answer:

1/3

Step-by-step explanation:

The slope increases by 1/3.

The slope formula is y2-y1/x2-x1.

When you plug in the points and simplify, you get 1/3.

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3 years ago

Each sentence shows the number of pages a student reads a book and the amount of time it takes to read those pages.

tatuchka [14]

Answer:

65 mins

Step-by-step explanation:

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3 years ago

Convert each of the following fractions into a decimals

Rufina [12.5K]

0.25
0.6
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3 years ago

Read 2 more answers

In a geometric sequence, the__ between consecutive terms is constant

kow [346]

Answer:

In a geometric sequence, the ratio between consecutive terms is constant.

Step-by-step explanation:

A geometric sequence is where you get from one term to another by multiplying by the same value. This value is known as the constant ratio, or common ratio. An example of a geometric sequence and it's constant ratio would be the sequence 4, 16, 64, 256, . . ., in which you find the next term by multiplying the previous term by four. 4 × 4 = 16, 16 × 4 = 64, and so on. So, in this sequence the constant ratio would be four.

3 0

3 years ago

1 х Given g(x)=

yarga [219]

(a) Since $g(x)=\sqrt[3]{x}$ and $h(x) = \frac1{x^3}$ , we have

$(g\circ h)(x) = g(h(x)) = g\left(\dfrac1{x^3}\right) = \sqrt{3}{\dfrac1{x^3}} = \dfrac1x$

We're given that

$(f \circ g \circ h)(x) = f(g(h(x))) = f\left(\dfrac1x\right) = \dfrac x{x+1}$

but we can rewrite this as

$\dfrac x{x+1} = \dfrac{\frac xx}{\frac xx + \frac1x} = \dfrac1{1+\frac1x}$

(bear in mind that we can only do this so long as x ≠ 0) so it follows that

$f\left(\dfrac1x\right) = \dfrac1{1+\frac1x} \implies \boxed{f(x) = \dfrac1{1+x}}$

(b) On its own, we may be tempted to conclude that the domain of $(f\circ g\circ h)(x) = \frac1{1+x}$ is simply x ≠ -1. But we should be more careful. The domain of a composite depends on each of the component functions involved.