How do you do surface area and volume?

2 answers:

5 0

Depending on what shape or figure you are talking about, generally volume= Bh B= area of the base and for area greatly depend on what the object is.
square= side cubed
rectangle= L time H
triangle= base time height divided by 2
circle= pi time radius cubed
that should get you through what you need.

marissa [1.9K]3 years ago

4 0

Prism; Surface area = Lateral Area + 2(base)
Volume = Base times height
Cylinder; surface area = lateral area + 2(base)
Volume = Base times height
Pyramid; Surface area = Lateral times base
Volume = 1/3 base times height
Cone; Surface area= Lateral area + base
Volume= 1/3 base times height

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andrey2020 [161]

Answer:

d = 8

Step-by-step explanation:

2(d -6) - 3 = 1

+3 +3

2(d-6) = 4

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3 years ago

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Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

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Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

notice that

$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

I hope this helsp you

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