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goldenfox [79]
1 year ago
15

Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Mathematics
1 answer:
Thepotemich [5.8K]1 year ago
6 0

\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

Explanation

\frac{1}{a+bi}=c+di

Step 1

multiplicate by the conjugate

\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}

notice that

\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\  \end{gathered}\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

I hope this helsp you

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Answer:

The sum of the first 20 terms is -1440.

Step-by-step explanation:

We want to find the sum of the first 20 terms of the arithmetic sequence:

4, -4, -12, -20...

The sum of an arithmetic sequence is given by:

\displaystyle S=\frac{k}{2}(a+x_k)

Where <em>k</em> is the number of terms, <em>a</em> is the initial term, and <em>x</em>_<em>k</em> is the last term.

Since we want to find the sum of the first 20 terms, <em>k</em> = 20.

Our initial term <em>a</em> is 4.

Our last term is also the 20th term as we want the sum of the first 20 terms.

To find the 20th term, we can write an explicit formula for our sequence. The explicit formula for an arithmetic sequence is given by:

x_n=a+d(n-1)

Where <em>a</em> is the initial term, <em>d</em> is the common difference, and <em>n</em> is the <em>n</em>th term.

Our initial term is 4. From the sequence, we can see that our common difference is -8 since each subsequent term is eight less than the previous term. Therefore:

x_n=4-8(n-1)

Then the last or 20th term is:

x_{20}=4-8(20-1)=4-8(19)=-148

Therefore, the sum of the first 20 terms are:

\displaystyle\begin{aligned} S_{20}&=\frac{(20)}{2}\left((4)+(-148))\\&=10(-144) \\&= -1440\end{aligned}

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2 years ago
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Answer: \dfrac{35}{6}\ \text{days},\ 35\ \text{days}

Step-by-step explanation:

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Suppose the other person take 6x days

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When they work together, it took them 5 days i.e.

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So, time taken by the to finish individually is given by

\Rightarrow \text{Andrew= }\dfrac{35}{6}\ \text{days}\\\\\Rightarrow \text{Other Person}=6\times \dfrac{35}{6}\\\\\Rightarrow \text{Other Person}=35\ \text{days}

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3 years ago
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Answer:

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