8,7,9,3,4,9,2
This is correct because I’m in middle school
32 models of 100. you are prone for elementary questions in all subjects and i accept that very dearly, thank you
All are equal except A/D = C/B
I replaced the values with numbers
a=5 b=10 c=50 d=100
10/5=100/50 so it’s not b/a = d/c
5/10=50/100 so it’s not a/b = c/d
5/50 = 10/100 so it’s not a/c = b/d
5/100 is NOT 50/10 so it’s NOT a/d = c/b
Hello!
We can solve this by using substitution
we can plug y = x - 1 into the other equation
So 2x - 3( x - 1) = -1
We can distribute the -3 to (x - 1)
2x - 3x + 3 = -1
Combine like terms
-x + 3 = -1
Subtract 3 from both sides
-x = -4
Since x is negative we can multiply both sides by -1
x = 4
We can plug x into the first equation
y = (4) - 1
y = 3
The answers are x = 4 and y = 3
Hope this helps!
Question 1:
For this case, the first thing we must do is define variables.
We have then:
x: number of nickels
y: number of dimes
We write the system of equations that adapts to the problem.
We have then:
0.05x + 0.10y = 6.10
x + y = 67
Solving the system we have:
x = 12
y = 55
Answer:
there are 12 nickels
Question 2:
For this case, the first thing we must do is define variables.
We have then:
x: Allan's score
y: Dave's score
We write the system of equations that adapts to the problem.
We have then:
x + y = 375
x = 2y-60
Solving the system we have:
x = 230
y = 145
Answer:
Dave: 145 Allan: 230
