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kumpel [21]
3 years ago
13

Cylinder A has a radius of 12 inches and a height of 6 inches. Cylinder B has a volume of 648π. What is the percent change in vo

lume between cylinders A and B?
Cylinder B is 50% smaller than cylinder A.
Cylinder B is 25% smaller than cylinder A.
Cylinder B is 150% bigger than cylinder A.
Cylinder B is 200% bigger than cylinder A.

B?
Mathematics
2 answers:
babunello [35]3 years ago
8 0
Ypu are correct again.
UNO [17]3 years ago
8 0

Answer:

Cylinder B is 25% smaller than cylinder

Step-by-step explanation:

Radius of cylinder A = 12 inches

Height of Cylinder A = 6 inches

So, volume of cylinder A = \pi r^{2} h

                                         = \pi (12)^{2} (6)

                                         = 864\pi

Volume of cylinder B = 648\pi

Difference in Volumes =  864\pi -648\pi

                                      =  216\pi

So, to find the percentage change in volume between cylinders A and B

\frac{216\pi}{864\pi} \times 100

25\%

Hence Cylinder B is 25% smaller than cylinder .

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