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3 years ago

Please help with these problems!!!

Mathematics

1 answer:

nataly862011 [7]3 years ago

3 0

Answer:

12345678901234567890

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Answer:

12/30

Step-by-step explanation:

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3 years ago

Brian needs to paint a logo using two right triangles. The dimensions of the logo are shown below. What is the difference betwee

solong [7]

Answer:

7.5 cm²

Step-by-step explanation:

Dimensions of the large ∆:

$base (b) = 3cm, height (h) = 9cm$

$Area = 0.5*b*h = 0.5*3*9 = 13.5 cm^2$

Dimensions of the small ∆:

$base (b) = 2cm, height (h) = 6cm$

$Area = 0.5*b*h = 0.5*2*6 = 6 cm^2$

Difference between the area of the large and the small ∆ = 13.5 - 6 = 7.5 cm²

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3 years ago

12-2/3x=x-18 so how do you answer this question

vitfil [10]

Answer:

Step-by-step explanation:

I think I've already answered this question.

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3 years ago

I’m stuck can some one help me

abruzzese [7]

Answer:

3) Midpoint is (-4,0.5)

Option A is correct.

4) Midpoint is (2.5,0)

Option B is correct.

5) The factors are (x+4)(x-7)

Option C is correct.

6) The factors are (x+4)(x+2)

Option A is correct.

Step-by-step explanation:

Question 3

Find midpoint of the following:

(2,-7), (-10,8)

The formula used to find midpoint is: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

We have $x_1=2, y_1=-7, x_2=-10,y_2=8$

Putting values and finding midpoint

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2-10}{2},\frac{-7+8}{2} )\\Midpoint=(\frac{-8}{2},\frac{1}{2} )\\Midpoint=(-4,0.5 )$

So, Midpoint is (-4,0.5)

Option A is correct.

Question 4

Find midpoint of the following:

(2,-10), (3,10)

The formula used to find midpoint is: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

We have $x_1=2, y_1=-10, x_2=3,y_2=10$

Putting values and finding midpoint

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2+3}{2},\frac{-10+10}{2} )\\Midpoint=(\frac{5}{2},\frac{0}{2} )\\Midpoint=(2.5,0 )$

So, Midpoint is (2.5,0)

Option B is correct.

Question 5

Factor each completely

$x^2-3x-28$

We will break the middle term and find factors

$x^2-3x-28\\=x^2-7x+4x-28\\Taking\:common\\=x(x-7)+4(x-7)\\=(x+4)(x-7)$

So, the factors are (x+4)(x-7)

Option C is correct.

Question 6

Factor each completely

$x^2+6x+8$

We will break the middle term and find factors

$x^2+6x+8\\=x^2+4x+2x+8\\=x(x+4)+2(x+4)\\=(x+4)(x+2)$

So, the factors are (x+4)(x+2)

Option A is correct.

7 0

3 years ago

I NEED HELP AS ASAP 4 THE FIRST AND SECOND ONE<br> !!!!

irga5000 [103]

Explaination: when graphing a relation, the set of second elements will be the y-values of the graph.
Range: [-4,-3,-2,0,3,5]

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3 years ago