1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tresset [83]
3 years ago
7

You have a balance of $4,500 on your credit card. The interest rate is 12% (1% per month). The late payment fee is $40. You miss

a payment. Solve for your fees plus interest for the month.
a) $40
b) $45
c) $65
d) $85
Mathematics
1 answer:
Montano1993 [528]3 years ago
3 0
I started by figuring out how much interest you get in a month by multiplying 4500 by .01. This gave me $45 as in interest. Then I added the payment fee, $40. 40+45 is 85, so the answer should be d). However, I'm not 100% positive. Somebody verify please? :)
You might be interested in
Ronny, Celina, Jack, and Michelle together placed a total of 20 brownies on a tray. Ronny placed 0.15 of the brownies, Celina pl
Marat540 [252]
To answer the question above, evaluate the number of cookies each of them placed on a tray. The calculations are shown below,
 
Ronny              C1 = 0.15 x 20 = 3
Celina              C2 = 3
Jack                 C3 = 0.30 x 20 = 6
Michelle           C4 = 20 - (3 + 3 + 6) = 8

From the calculation above, <em>Michelle</em> placed the most number of brownies on the tray. 

3 0
4 years ago
Read 2 more answers
A star in the sky appears to move by 12 arcseconds over the course of 6 months. Convert this number into first areminutes then d
Bumek [7]

Answer:

Given :A star in the sky appears to move by 12 arc seconds over the course of 6 months.

To Find :Convert this number into first arc minutes then degrees.

Solution:

60 arc seconds = 1 arc minute

1 arc seconds = \frac{1}{60} arc minute

12 arc seconds = \frac{1}{60} \times 12 arc minute

12 arc seconds = \frac{1}{5} arc minute

So, 12 arc seconds = \frac{1}{5} arc minute

Now convert it into degrees

60 arc minute = 1 degree

1 arc minute = \frac{1}{60} degree

\frac{1}{5} arc minute = \frac{1}{60} \times \frac{1}{5} degree

\frac{1}{5} arc minute = \frac{1}{300} degrees

12 arc seconds = \frac{1}{300} degrees

8 0
3 years ago
A pipe is leaking and 1.5 cups per day about how many gallons per week is the pipe leaking
MatroZZZ [7]
The question asks per week. So 1.5 cups times 7 days is 10.5 cups. 

<span>The pipe leaks </span>10.5 cups<span> every week.</span>
7 0
3 years ago
Read 2 more answers
Solve for x in the equation 3 x squared minus 18 x + 5 = 47.
ryzh [129]

Answer:

x= 3 +\sqrt{23}, 3 -\sqrt{23}

Step-by-step explanation:

You use the quadratic formula to get x= \frac{18+6\sqrt{23} }{6} ,\frac{18-6\sqrt{23} }{6}

Then you simplify and get the answers x= 3 +\sqrt{23}, 3 -\sqrt{23}

​​  

​​  

6 0
3 years ago
Read 2 more answers
HELP ASAP. please show work tysm! solve for x
nata0808 [166]

Answer:

71

Step-by-step explanation:

vertical sides  are congruent

x+30=101

x=71

7 0
3 years ago
Other questions:
  • Pablo drove 23.1 miles to his aunt’s house, then drove 19.24 miles to his friend’s house. Which estimate can Pablo use to determ
    12·2 answers
  • What value of k makes the equation true? 12 (–17) = –17 + k
    15·1 answer
  • Pls solve number 6 in this question
    13·1 answer
  • Find parametric equations for the line through (3, 1, 4) that is perpendicular to the plane x ? y + 2z = 9. (use the parameter t
    9·1 answer
  • What the answer now
    6·1 answer
  • What is the mode of the following data values? 54, 78, 36, 46, 36
    12·2 answers
  • Points P. Q. and S are on a circle. The measure of arc PQ is 58°<br>What is the measure of arc PSQ?​
    13·1 answer
  • A hockey puck has a height of -2.5 cm. What is the height of 7 hockey pucks?
    12·1 answer
  • 5r-8=9r-12 answer this plsss
    7·1 answer
  • What is the local tax deducted for $562 biweekly with 2 1/2% tax? $14.05 $ $21.10 $28.10 $140.50​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!