Answer:
x=2, z=4, y=-6
Step-by-step explanation:
Add
<u>-9x-y+2z= -4</u>
<u>-6x+y+5z= 2</u>
-9x-6x is -15x
-y+y is 0
2z+5z is 7z
-4+2 is -2
So the equation now looks like this: -15x+7z=-2
Subtract
<u>-6x+y+5z= 2</u>
<u>-4x+y+5z= 6</u>
So the equation will look like this:
<u>-6x+y+5z= 2</u>
<u>-(-4x+y+5z= 6)</u>
-6x+4x is -2x
y-y is 0
5z-5z is 0
2-6 is -4
So the equation now looks like this: <u>-2x=-4</u>
You can find x by dividing -2 on both sides:
<u>x=2 </u>
So 2 is x
Now you can substitute x into 2
-15(2)+7z=-2
-30+7z=-2
7z=28
Divide 7 on both sides:
<u>z=4</u>
So now you can substitute z into 4 (For any of the three equation)
-4(2)+y+5(4)=6
-8+y+20=6
20 minus 8 is 12
y+12=6
Subtract 12 on both sides:
y=-6
So the answers are
x=2, z=4, y=-6
Hope this helps!
f(x)=x-4f(3)=3-4so f(3)= -1
Answer:
(Choice A)
Juanita gets a strike next game.'
Step-by-step explanation:
Your question is obviously incomplete.
Complete question is:
Juanita and Nina are bowling together. The probability of Juanita getting a strike next game is 24%. The probability of Nina getting a strike next game is 0.17. Which of these events is more likely?
(Choice A)
Juanita gets a strike next game.'
(Choice B)
Nina gets a strike next game.
(Choice C)
Neither. Both events are equally likely.
Answer:
Probability of Juanita : P(J)= 24% => 0.24
probability of Nina getting a strike next game: P(N) = 0.17
As you can see 0.24 > 0.17 ----> P(J)>P(N)
Thus it can be concluded that Juanita gets a strike next game is more likely.
so, choice A
