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3 years ago

PLEASE HELP ASAP I NEED HELP RNN PLEASE

Mathematics

2 answers:

Triss [41]3 years ago

4 0

Answer:

The first answer on the right side

Step-by-step explanation:

-Dominant- [34]3 years ago

3 0

Answer:

it is option 2 which is height or altitude^2 + base^2=x^2

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The length of a rectaangle 48 centimeters. The relationship between the length, the width, and the perimeter of the rectangle ca

Monica [59]

Answer:

Step-by-step explanation:

We are told that the perimeter is 48 = 2L + 2W. This reduces to

24 = L + W. Next, substitute, one by one, the 3 widths 10 cm, 3.6 cm and w cm:

a) If W = 10 cm, 24 = L + W becomes 24 = L + 10, or L = 14 cm

b) If W = 3.6 cm, 24 = L + W becomes 24 = L + 3.6, or L = 20.6 cm

c) If W = w, 24 L + W becomes 24 = L + w, so that L = (24 - w) cm

4 0

3 years ago

What is the area of a circle with a radius of 6 inches?

Vika [28.1K]

Answer:

The answer to your question is 113.04 in²

Step-by-step explanation:

To solve this problem substitute the values in the formula and simplify.

Data

Area = ?

radius = 6 in

π = 3.14

Formula

Area = π x r²

Substitution

Area = (3.14) x (6)²

Simplification

Area = 3.14 x 36

Result

Area = 113.04 in²

7 0

3 years ago

Kallah needs to buy ribbon for a sewing project. The fabric store charges 2 dollars per meter. How much will it cost Kallah to b

Zinaida [17]

There are 100 cm in a meter
$1.50 for 75 cm.

3 0

3 years ago

Read 2 more answers

Pls help asap i’m timed!!!

frutty [35]

This is ed right? If so the answer would be c

8 0

3 years ago

Read 2 more answers

Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp

olga55 [171]

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = $\overline{x}$ = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data speeds i.e. x - $\overline{x}$

x - $\overline{x}$ = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between carrier's highest data speed and the mean of all 50 data speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

$\frac{59.98}{20.03}=2.99$

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

$z=\frac{x-\overline{x}}{s}$

Using the given values, we get:

$z=\frac{75.6-15.62}{20.03}=2.99$

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the carrier's highest data speed is significantly higher.

3 0

3 years ago