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2 years ago

Foston is directly between liberty and west Quall and is 4 inches from liberty on the map .how far is foston from west quall

2 answers:

6 0

IF Foston is directly between this means Foston is y the middle, so there is the same distance from Foston to Liberty and from Foston to West Quall = 4 inches

balu736 [363]2 years ago

4 0

Foston is 4 inches away from west quall on the map. this is so because x, Foston, is in the middle of both places.

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marta is trying to decide between two jobs the first job will pay 35,340 and the second job will pay 36,120 before taxes which j

Makovka662 [10]

Martha will get a higher salary with the first option because the more you make the more taxes are taken out of your salary

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2 years ago

Read 2 more answers

Which expression is equivalent to (x^1/2y^-1/4z)^-2?

tiny-mole [99]

Answer:

y^1/2/xz^2 option 3

Step-by-step explanation:

(x^1/2 y^-1/4 z)^-2= x^(-1/2*2) y^(1/4*2) z^-2= x^-1 y^1/2 z^-2= y^1/2/xz^2

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2 years ago

-3/4÷-1/2<br><br>pls help armieee

PilotLPTM [1.2K]

Answer:

exact form : 3/2

decimal form 1.5

mixed number form 1 1/2

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2 years ago

Week 1 2 3 4 5 Water Level (inches) − 1 1 4 1 3 8 2 1 2 − 1 5 8 − 1 3 4 Between which two weeks did the water level change the m

suter [353]

Answer:

The water level change the most in week 3 and week 4

The change = -370 inches

Step-by-step explanation:

Given - Week 1 2 3 4 5

Water Level (inches) − 1 1 4 1 3 8 2 1 2 -1 5 8 -1 3 4

To find - Between which two weeks did the water level change the most? Calculate the change .

Proof -

The formula for change in water level with respect to week be-

Rate of Change in Water Level = Difference in water level / Difference in weeks

Now,

For week 1 and week 2

Rate of change in water level = $\frac{138 - 114}{2 - 1}$ = $\frac{24}{1}$ = 24 inches

Now,

For week 1 and week 3

Rate of change in water level = $\frac{212 - 114}{3 - 1}$ = $\frac{98}{2}$ = 49 inches

Now,

For week 1 and week 4

Rate of change in water level = $\frac{-158 - 114}{4 - 1}$ = $-\frac{272}{3}$ = -90.67 inches

Now,

For week 1 and week 5

Rate of change in water level = $\frac{-134 - 114}{5 - 1}$ = $-\frac{248}{4}$ = -62 inches

Now,

For week 2 and week 3

Rate of change in water level = $\frac{212 - 138}{3 - 2}$ = $\frac{74}{1}$ = 74 inches

Now,

For week 2 and week 4

Rate of change in water level = $\frac{-158 - 138}{4 - 2}$ = $-\frac{296}{2}$ = -148 inches

Now,

For week 2 and week 5

Rate of change in water level = $\frac{-134 - 138}{5 - 2}$ = $-\frac{272}{3}$ = -90.67 inches

Now,

For week 3 and week 4

Rate of change in water level = $\frac{-158 - 212}{4 - 3}$ = $-\frac{370}{1}$ = -370 inches

Now,

For week 3 and week 5

Rate of change in water level = $\frac{-134 - 212}{5 - 3}$ = $-\frac{346}{2}$ = 173 inches

Now,

For week 4 and week 5

Rate of change in water level = $\frac{-134 + 158}{5 - 4}$ = $\frac{24}{1}$ = 24 inches

∴ we get

The water level change the most in week 3 and week 4

The change = -370 inches

Note :

The highest change means which temperature goes the most change in water level. It can be negative also.

So, We have to take the modulus and then find the highest number.

Here, 370 > 173

So, Highest change occurs in Week 3 and Week 4 but not in Week 3 and Week 5.

7 0

2 years ago

1/4 = x/12 solve for x

Vedmedyk [2.9K]

Answer: x=3
First you cross multiply
Next you swap sides then divide both sides by 4

6 0

2 years ago