The common ratio of 2, 10/3, 50/9 is 
<u>Solution:</u>
Given, series of elements are 
We have to find the common ratio of the above given series.
We know that, common ratio of an G.P is division of any number in that series with the previous number of the series.
So, now take
and 2


Hence, the common ratio of the given series is 
Hello!
We can make an equation based on what we know
The product of 9 and a number is
9 * x
Added to six
9 * x + 6
Gives the result of 24
9 * x + 6 = 24
Now you solve it algebraically
Subtract 6 from both sides
9 * x = 18
Divide both sides by 9
x = 2
The answer is 2
Hope this helps!
<span>x − y ≥ 3 ... > stands for above on a graph, and the line under it _ stands for shaded.</span>
Answer:
£18
Step-by-step explanation:
Let
x = original price of the game
Increase in price = 1/2
New price = £27
x + 1/2x = £27
2x+x/2 = 27
3/2x = 27
x = 27 ÷ 3/2
= 27 × 2/3
= 54 / 3
x = £18
Therefore, the original price of the game is £18
Answer:
Error
Step-by-step explanation:
(-94)/5+22/22 Given
-18.8+1 PEMDAS (do -94/5 and 22/2)
-17.8 Add the numbers
After you add the numbers, you take the square root. you will get the answer "Error" because you cannot take the square root of a negative number