U(x) = f(x).(gx)
v(x) = f(x) / g(x)
Use chain rule to find u(x) and v(x).
u '(x) = f '(x) g(x) + f(x) g'(x)
v ' (x) = [f '(x) g(x) - f(x) g(x)] / [g(x)]^2
The functions given are piecewise.
You need to use the pieces that include the point x = 1.
You can calculate f '(x) and g '(x) at x =1, as the slopes of the lines that define each function.
And the slopes can be calculated graphycally as run / rise of each graph, around the given point.
f '(x) = slope of f (x); at x = 1, f '(1) = run / rise = 1/1 = 1
g '(x) = slope of g(x); at x = 1, g '(1) = run / rise = 1.5/ 1 = 1.5
You also need f (1) = 1 and g(1) = 2
Then:
u '(1) = f '(1) g(1) + f(1) g'(1) = 1*2 + 1*1.5 = 2 + 1.5 = 3.5
v ' (x) = [f '(1) g(1) - f(1) g(1)] / [g(1)]^2 = [1*2 - 1*1.5] / (2)^2 = [2-1.5]/4 =
= 0.5/4 = 0.125
Answers:
u '(1) = 3.5
v '(1) = 0.125
The answer is B.
This is because A is incorrect, Zach number of minutes didnt increase by an equal factor every month.
C and D are incorrect, Victoria's methods aren't exponential, but Zach's are.
So that leaves the only reasonable answer which is B.
= 2a - 1
2() = 2(2a - 1) <em>multiplied both sides by 2 </em>
ab = 4a - 2 <em>distributed the 2 on the right side</em>
ab - 4a = -2 <em>subtracted 4a from both sides</em>
a(b - 4) = -2 factored out "a" from the left side
a = 
<em>divided (b - 4) on both sides</em>
Answer: a =
