Answer:
The vertex: 
The vertical intercept is: 
The coordinates of the two intercepts of the parabola are
and 
Step-by-step explanation:
To find the vertex of the parabola
you need to:
1. Find the coefficients <em>a</em>, <em>b</em>, and <em>c </em>of the parabola equation
<em>
</em>
2. You can apply this formula to find x-coordinate of the vertex
, so

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex (
)

To find the vertical intercept you need to evaluate x = 0 into the parabola equation

To find the coordinates of the two intercepts of the parabola you need to solve the parabola by completing the square











Answer:
Since Darcie wants to crochet a minimum of 3 blankets and she crochets at a rate of 1/5 blanket per day, we can determine how many days she will need to crochet a minimum of 3 blankets following the next steps:
- Finding the number of days needed to crochet one (1) blanket:
\begin{gathered}1=\frac{1}{5}Crochet(Day)\\Crochet(Day)=5*1=5\end{gathered}
1=
5
1
Crochet(Day)
Crochet(Day)=5∗1=5
So, she can crochet 1 blanket every 5 days.
- Finding the number of days needed to crochet three (3) blankets:
If she needs 5 days to crochet 1 blanket, to crochet 3 blankets she will need 15 days because:
\begin{gathered}DaysNeeded=\frac{NumberOfBlankets}{Rate}\\\\DaysNeeded=\frac{3}{\frac{1}{5}}=3*5=15\end{gathered}
DaysNeeded=
Rate
NumberOfBlankets
DaysNeeded=
5
1
3
=3∗5=15
- Writing the inequality
If she has 60 days to crochet a minimum of 3 blankets but she can complete it in 15 days, she can skip crocheting 45 days because:
AvailableDays=60-RequiredDaysAvailableDays=60−RequiredDays
AvailableDays=60-15=45DaysAvailableDays=60−15=45Days
So, the inequality will be:
s\leq 45s≤45
The inequality means that she can skip crocheting a maximum of 45 days since she needs 15 days to crochet a minimum of 3 blankets.
Have a nice day!
The student is correct. Due to the meaning of perimeter which is all sides added up to make a number total, it is possible for a square and a rectangle to have the same perimeter if the numbers add up.
By applying the knowledge of similar triangles, the lengths of AE and AB are:
a. 
b. 
<em>See the image in the attachment for the referred diagram.</em>
<em />
- The two triangles, triangle AEC and triangle BDC are similar triangles.
- Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.
<em>This implies that</em>:
<em><u>Given:</u></em>

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>
EC/DC = AE/DB



<u>b. </u><u>Find the length of </u><u>AB:</u>

AC = 6.15 cm
To find BC, use AC/BC = EC/DC.




Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:
a. 
b. 
Learn more here:
brainly.com/question/14327552
Answer: An expression for the height is: H = (3/64)V
To start with, we will assume that it is a square pyramid, meaning all the sides of the base are 8 feet wide.
Now, we need the formula for the volume of a square pyramid.
V = BH/3
We know the area of the base, it is 8 x 8 = 64, so we can input that.
V = 64H/3 We can multiply by 3/64 to find an expression for the height of the fort.
(3/64)V = H