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3 years ago

Sam is 6 years older than marlon. The sum of their ages is 30. Find Sam and marlons age.

Mathematics

2 answers:

AnnZ [28]3 years ago

7 0

Sam is 18 and Marlon is 12 :)

Triss [41]3 years ago

6 0

Answer:

Sam = 18 and Marlon = 12

Step-by-step explanation:

If Sam is 6 years older but added is 30 then Sam could 18 and Marlon 12.

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Find the limit, if it exists.<br> Picture provided below.

Alja [10]

The answer is 20 because you plug in x=2 into f(x)

$3 \times 2 {}^{3} + 2^{2} - 8 = 20$

7 0

3 years ago

Gabrielle is baking large batches of brownies and cookies to share with her friends and family. Among other ingredients, her bro

USPshnik [31]

The system of inequalities can model Gabrielle’s situation is;

x + 2y ≤ 20

x + 2y ≤ 203x + 2y ≤ 21

<h3>Inequality</h3>

It follows from the task content, that the inequalities which can be used to model Gabrielle's situation be determined.

By setting variables as follows;

batches of brownies = x
batches of cookies = y

Brownie:

Sugar = 1 cup

Eggs = 2

Cookie:

Sugar = 3 cups

Eggs = 2

x + 2y ≤ 20

x + 2y ≤ 203x + 2y ≤ 21

Learn more about inequality:

brainly.com/question/25275758

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5 0

2 years ago

Which figures are polygons

TiliK225 [7]

Answer:d the arrow

Step-by-step explanation:

7 0

3 years ago

Which of the following sums would be under the radical symbol to find the distance between the points (7, -1) and (-8, -9)?

Alexxandr [17]

Sadly, you didn't put any sums on your list of choices.
In fact, I can't even find a list of choices !

To find the distance between (7, -1) and (-8, -9),
you would build a sum under a square-root (radical)
symbol, and it would look something like this:

√ ( 225 + 64 ) .

5 0

3 years ago

Read 2 more answers

Rebecca has 12 photos she wants to hang side by side on her wall.A. If she only wants to display 8 of the photos, in how many wa

Mariana [72]

If she will choose 8 from 12 photos, the total number of ways she can choose is given by a combination of 12 choose 8, since the order of the photos doesn't matter.

The formula for a combination of n choose p is:

$C(n,p)=\frac{n!}{p!(n-p)!}$

For n = 12 and p = 8, we have:

$C(12,8)=\frac{12!}{8!(12-8)!_{}}=\frac{12\cdot11\cdot10\cdot9\cdot8!}{8!\cdot4!}=\frac{12\cdot11\cdot10\cdot9}{4\cdot3\cdot2}=495$

So there are 495 ways.

If she wants to arrange the 12 photos, the total number of ways is given by the factorial of 12:

$12!=12\cdot11\cdot10\cdot9\cdot8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2=479001600$

There are 479,001,600 ways.

Since 10 photos already have specific places, we need to calculate the number of ways to arrange the other two photos in the two remaining places.

In this case, there are only 2 ways of organizing the remaining two photos:

Photo 1 first, photo 2 last, or photo 1 last and photo 2 first.

6 0

1 year ago