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WITCHER [35]
3 years ago
9

Most queries have fully meets results

Computers and Technology
1 answer:
liq [111]3 years ago
8 0
True. Most queries have fully meets results, those queries who have completely satisfied the user's standards of queries. For example if a user searches for something in a website then the website which the user's is on makes super fast process and satisfies the user.
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Write a Java program to create a class called Cars. The class should include three instance variables: makes (type: String), mod
Fiesta28 [93]

Answer:

Explanation:

This code was written in Java. It creates the Cars class with the requested variables and methods. It also creates the TestCars class which asks the user for the necessary inputs and then creates three Cars objects and passes the input values to the constructors. Finally, it uses the show() method on each object to call the information. A test has been created and the output can be seen in the attached image below.

import java.util.Scanner;

class TestCars{

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.print("Enter Car Make: ");

       String make1 = in.next();

       System.out.print("Enter Car Model: ");

       String model1 = in.next();

       System.out.print("Enter Car Year: ");

       int year1 = in.nextInt();

       System.out.print("Enter Car Make: ");

       String make2 = in.next();

       System.out.print("Enter Car Model: ");

       String model2 = in.next();

       System.out.print("Enter Car Year: ");

       int year2 = in.nextInt();

       System.out.print("Enter Car Make: ");

       String make3 = in.next();

       System.out.print("Enter Car Model: ");

       String model3 = in.next();

       System.out.print("Enter Car Year: ");

       int year3 = in.nextInt();

       Cars car1 = new Cars(make1, model1, year1);

       Cars car2 = new Cars(make2, model2, year2);

       Cars car3 = new Cars(make3, model3, year3);

       car1.show();

       car2.show();

       car3.show();

   }

}

class Cars {

   String makes, models;

   int years;

   public Cars(String makes, String models, int years) {

       this.makes = makes;

       this.models = models;

       this.years = years;

   }

   public void show() {

       System.out.println("Car's make: " + this.makes);

       System.out.println("Car's model: " + this.models);

       System.out.println("Car's year: " + this.years);

   }

}

5 0
3 years ago
How are network computers different from traditional personal computers? describe some usage scenarios in which it is advantageo
Elanso [62]
A network computer depend on on a centralized computer for most of its services. It can consequently have a minimal operating system while a personal computer on the other hand has to be proficient of on condition that all of the required functionality in a detached manner without depending on a centralized manner. Scenarios where administrative costs are high and where sharing leads to more efficient use of resources are exactly those settings where network computers are preferred.
8 0
4 years ago
Power brakes:
IgorLugansk [536]
The answer is B becausePower brakes are a system of hydraulics used to slow down or stop most motor vehicles. It uses a combination of mechanical components to multiply the force applied to the brake pedal by the driver into enough force to actuate thebrakes and stop a vehicle that can weigh several tons.
5 0
3 years ago
Read 2 more answers
The open items on your computer are displayed here. menu bar open bar taskbar toolbar
Dennis_Churaev [7]
Maybe the answer is the Taskbar?
8 0
3 years ago
Read 2 more answers
Using the XML Document below (library with books), define the following queries in XQuery: (a) Give the titles of all Books sort
Softa [21]

Answer:

Explanation:

a)use order by clause for sorting

for $x in doc("books.xml")/bib/book order by xs:float($x/price) return $x/title (default sorted in ascending order)

or

for $x in doc("books.xml")/bib/book order by xs:float($b/price) descending  return $b/title (sorted in descending order)

b)doc("books.xml")//book[author = 'Abiteboul']

c)for $x in distinct-values(doc("bib.xml")/bib/book/author)

return <res>

<name>{$x}</name>

<count>

 {count (doc("bib.xml")//book[exists(indexof(author,$x))]) }

</count>

<res>

3 0
3 years ago
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