Answer:
public static double convertToInches(double numFeet, double numInches){
return (numFeet*12)+numInches;
}
Explanation:
This technique of having more than one method/function having the same name but with different parameter list is called method overloading. When the method is called, the compiler differentiates between them by the supplied parameters. The complete program is given below
public class FunctionOverloadToInches {
public static void main(String[] args) {
double totInches = 0.0;
totInches = convertToInches(4.0, 6.0);
System.out.println("4.0, 6.0 yields " + totInches);
totInches = convertToInches(5.9);
System.out.println("5.9 yields " + totInches);
return;
}
public static double convertToInches(double numFeet)
{
return numFeet * 12.0;
}
/* Your solution goes here */
public static double convertToInches(double numFeet, double numInches){
return (numFeet*12)+numInches;
}
}
I think the question is referring to the tab key.
It may have been a songlyrics
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
Free Wi-Fi is typically offered on public network
