Answer:
x = 2 and y =
Step-by-step explanation:
y = 2x - 1
y = -x + 5
2x - 1 = -x + 5
2x + x = 5 + 1
3x = 6
x = 6/3
x = 2
y = 2(3)-1
y = 5
Answer:
=−5.75x−17.4
Step-by-step explanation:
=−0.25x−8+−1(5.5x+9.4)
=−0.25x+−8+−1(5.5x)+(−1)(9.4)
=−0.25x+−8+−5.5x+−9.4
another way >>>><<<<
=−0.25x+−8+−5.5x+−9.4
=(−0.25x+−5.5x)+(−8+−9.4)
=−5.75x+−17.4
Answer:
=−5.75x−17.4
111.28 1/8=0.125 0.125*890.20=111.275 money can only have 2 decimals so round up and $111.28 is your answer.
In a trapezoid, two opposite sides are parallel and are called bases.
In this trapezoid, the top and bottom sides are parallel and are the bases.
The right side that intersects both bases is a transversal.
When parallel lines are cut by a transversal, same-side interior angles are supplementary. The measures of supplementary angles add to 180 deg.
x + 72 = 180
x = 180 - 72
x = 108 deg
Answer : 4 times
Here it's given that ,
- The height and base of the butterfly sitting on the stem (red butterfly) is two times greater than the height and base of the butterfly sitting on the flower .
And we need to find out how many times the area of red winged butterfly is greater than that of sitting on the flower (blue butterfly) .
Let us take ,
- base of blue butterfly be b
- height of blue butterfly be h
- Area be A .
Then ,
- base of red butterfly will be 2b .
- height of red butterfly will be 2h .
- Area be A' .
We know that ,
→ area of the triangle = 1/2 × base × height
So that ,
→ A/A' = (1/2 * b * h) ÷ (1/2 *2b *2h)
→ A/A' = bh/4bh
→ A/A' = 1/4
→ A' = 4A
<u>Henceforth</u><u> the</u><u> area</u><u> of</u><u> </u><u>blue</u><u> butterfly</u><u> is</u><u> </u><u>4</u><u> </u><u>times </u><u>greater</u><u> than</u><u> </u><u>that</u><u> of</u><u> </u><u>red </u><u>winged</u><u> butterfly</u><u> </u><u>.</u>
I hope this helps.