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DochEvi [55]
3 years ago
14

Factor completely: 16-2x^3

Mathematics
1 answer:
Solnce55 [7]3 years ago
4 0

16-2x^3=2(8-x^3)=2(2^3-x^3)\\\\\text{use}\ a^3-b^3=(a-b)(a^2-ab+b^2)\\\\=2(2-x)(2^2+2x+x^2)\\\\=\boxed{2(2-x)(4+2x+x^2)}

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The least number of point the team could have scored is the LCM of the factors given = 60.

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The positive integers that can divide a number evenly are referred to as factors. Let's say we multiply two numbers to produce a result. The product's factors are the number that is multiplied.

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brainly.com/question/20739723

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6 0
1 year ago
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3 years ago
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Answer:

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3 years ago
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