3 years ago

Factor completely: 16-2x^3

1 answer:

4 0

$16-2x^3=2(8-x^3)=2(2^3-x^3)\\\\\text{use}\ a^3-b^3=(a-b)(a^2-ab+b^2)\\\\=2(2-x)(2^2+2x+x^2)\\\\=\boxed{2(2-x)(4+2x+x^2)}$

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3 years ago

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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Someone please help me!

Lerok [7]

Answer:

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When you take the cube root of -27, -3 is your answer. To double check, just cube -3 (or -3 x -3 x -3) and you can see you get -27.

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