3 years ago

How does the term linear pair describe how and angle looks

1 answer:

3 0

It describes how it looks because when your talking linear you talking about graphing in order to do a angle you have to use linear

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If f'(0) = 5 and F(x) = f(3x), what is F'(0)?

Llana [10]

Answer:

$\displaystyle F'(0) = 15$

Step-by-step explanation:

We are given that:

$f'(0) = 5 \text{ and } F(x) = f(3x)$

And we want to find F'(0).

First, find F(x):

$\displaystyle F'(x) = \frac{d}{dx}\left[ f(3x)]$

From the chain rule:

$\displaystyle \begin{aligned} F'(x) &= f'(3x) \cdot \frac{d}{dx} \left[ 3x\right] \\ \\ &= 3f'(3x)\end{aligned}$

Then:

$\displaystyle \begin{aligned} F'(0) & = 3f'(3(0)) \\ \\ & = 3f'(0) \\ \\ & = 3(5) \\ \\ & = 15\end{aligned}$

In conclusion, F'(0) = 15.

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3 years ago

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A large container holds 8 gallons of water. It begins leaking at a constant rate. After 48 minutes, the container has 5 gallons

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Whats the question?????????

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4 years ago

Find the scale factor of the small triangle to the large triangle.

Korvikt [17]

Answer:

scale factor is: 2.25

Step-by-step explanation:

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3 years ago

In the diagram of RST, what are the two smaller angles?

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Step-by-step explanation:

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3 years ago

If tan (theta) =5/4 and cos (theta) < 0 . Find the other trig. functions.

andrew-mc [135]

Tan(theta) = 5/4
sin(theta)/cos (theta)=5/4
cos(theta)=4sin(theta)/5
sin²(theta)+cos²(theta)=1
sin²(theta)+16sin²(iheta)/25=1 /*25
25 sin²(theta)+16 sin²(theta)=25
sin²(theta)=25/41 /√
sin(theta)= $\frac{-5 \sqrt{41} }{41}$
cos(theta)= $\frac{-4 \sqrt{41} }{41}$
cot(theta)= $\frac{4}{5}$
csc(theta)=1/sin(theta)= $\frac{- \sqrt{41} }{5}$
sec(theta)=1/cos(theta)= $\frac{- \sqrt{41} }{4}$

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3 years ago