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Anna35 [415]
3 years ago
5

In the diagram of RST, what are the two smaller angles?

Mathematics
1 answer:
ruslelena [56]3 years ago
6 0

Answer:

34

Step-by-step explanation:

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Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
A civil engineer is designing a public parking lot for the new town hall. The number of cars in each row should be six less than
alisha [4.7K]

The equation which the civil engineer can use to find the number of rows is 2x² - 12x = 112. Option D

<h3>How to determine the equation</h3>

Let the number of rows be x

Number of cars in each row = x - 6 = 56

Number of rows for parking lot = 2x

Then,

Number of cars for new parking lot = 2x ( x - 6 = 56)

Expand the expression,

2 ( x - 6 = 56)

2x² - 12x = 112

Thus, the equation which the civil engineer can use to find the number of rows is 2x² - 12x = 112. Option D

Learn more about word problems here:

brainly.com/question/1781657

#SPJ1

7 0
1 year ago
Hi there! Can someone help me with this, i need a proper answer, i don't need LINKS or FILES for the explanations.
alexira [117]

Answer:

<u>Using below system of inequalities</u>

  • y > 2x - 3
  • y < x + 1

<u>Following the rules </u>

  • 1. Finding x- and y - intercepts
  • 2. Connecting with dotted line for each as no equal symbol present in any inequality
  • 3. Shade respective regions
  • 4. Solution is the intersection of the shades regions
  • 5. Select any three points in the solution region

<u>Line 1</u>

  • y > 2x - 3
  • x- intercept: y = 0 ⇒ 0 = 2x - 3 ⇒ 2x = 3 ⇒ x = 1.5
  • y - intercept: x = 0 ⇒ y = -3
  • Shaded region is above the line (or to the left)

<u>Line 2</u>

  • y < x + 1
  • x- intercept: y = 0 ⇒ 0 = x + 1 ⇒ x = -1
  • y - intercept: x = 0 ⇒ y = 1
  • Shaded region is below the line (or to the right)

<u>Selected points are:</u>

  • (-1, -1), (1, 1), (2, 2)

4 0
2 years ago
PLEASE HELP ASAP RN!!!!!!
Anika [276]

Answer:

3sqrt(2)

Step-by-step explanation:

sqrt(32) - sqrt(2)

rewriting sqrt(32)

sqrt(16*2) - sqrt(2)

sqrt(16) * sqrt(2)  - sqrt(2)

4 sqrt(2) - sqrt(2)

3sqrt(2)

8 0
3 years ago
Can someone help me with this 4 - 3m &gt; -5
ella [17]

Answer: M < -3

.................................................

Step-by-step explanation:

4 - 3m > -5

4 - 3m > (-4 -5)

3m > -9

(3/3)m > (-9/3)

m<-3

4 0
3 years ago
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