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Vedmedyk [2.9K]
3 years ago
5

A search engine company needs to do a significant amount of computation every time it recompiles its index. For this task, the c

ompany has a single large supercomputer, and an unlimited supply of high-end PCs. They have broken the overall computation into n distinct jobs, labeled J1, J2, …, Jn, which can be performed completely independently of one another. Each job consists of two stages: first it needs to be preprocessed on the supercomputer, and then it needs to be finished on one of the PCs. Let’s say that job Ji needs pi seconds of time on the supercomputer, followed by fi seconds of time on a PC. Since there are at least n PCs available on the premises, the finishing of the jobs can be performed fully in parallel – all the jobs can be processed at the same time. However, the supercomputer can only work on a single job at a time, so the system managers need to work out an order in which to feed the jobs to the supercomputer. As soon as the first job in order is done on the supercomputer, it can be handed of to a PC for finishing; at that point in time a second job can be fed to the supercomputer; when the second job is done on the supercomputer, it can proceed to a PC regardless of whether or not the first job is done (since the PCs work in parallel); and so on. Let’s say that a schedule is an ordering of the jobs for the supercomputer, and the completion time of the schedule is the earliest time at which all jobs will have finished processing on the PCs. This is an important quantity to minimize, since it determines how rapidly El Goog can generate a new index.
(A) Give a polynomial-time algorithm that finds a schedule with as small a completion time as possible.

Computers and Technology
1 answer:
romanna [79]3 years ago
5 0

Answer:

See attached pictures for detailed answer.

Explanation:

See attached pictures for explanation.

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What action makes RAM on your computer disappear?
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alex41 [277]

Answer:

Modern (i.e 386 and beyond) x86 processors have eight 32-bit general purpose registers, as depicted in Figure 1. The register names are mostly historical. For example, EAX used to be called the accumulator since it was used by a number of arithmetic operations, and ECX was known as the counter since it was used to hold a loop index. Whereas most of the registers have lost their special purposes in the modern instruction set, by convention, two are reserved for special purposes — the stack pointer (ESP) and the base pointer (EBP).

For the EAX, EBX, ECX, and EDX registers, subsections may be used. For example, the least significant 2 bytes of EAX can be treated as a 16-bit register called AX. The least significant byte of AX can be used as a single 8-bit register called AL, while the most significant byte of AX can be used as a single 8-bit register called AH. These names refer to the same physical register. When a two-byte quantity is placed into DX, the update affects the value of DH, DL, and EDX. These sub-registers are mainly hold-overs from older, 16-bit versions of the instruction set. However, they are sometimes convenient when dealing with data that are smaller than 32-bits (e.g. 1-byte ASCII characters).

When referring to registers in assembly language, the names are not case-sensitive. For example, the names EAX and eax refer to the same register.

Explanation:

5 0
3 years ago
Write a C++ program that searches for anagrams in a dictionary. An anagram is a word obtained by scrambling the letters of some
Semmy [17]

Answer:

d, avt, car, feet, more, pitch, rome, tac, teef,

Anagrams of b in dictionary

Anagrams of cat in dictionary

avt, cat, tac,

Anagrams of room in dictionary

more, rome,

Anagrams of hello in dictionary

Anagrams of  in dictionary

Explanation:

// FindAnagrams.cpp : it is the starting point of application console.

//

#include <vector>

#include <hash_map>

#include <iostream>

#include <string>

#include <algorithm>

#include <map>

#include <set>

using namespace std;

using namespace stdext;

bool IsAnagrams(string& strA, string& strB)

{

   list<char> listA(strA.begin(), strA.end());

   list<char> listB(strB.begin(), strB.end());

   listA.sort();

   listB.sort();

   return listA == listB;

   // return equal(listA.begin(), listA.end(), listB.begin());

}

string SortChars(string str)

{

   list<char> l(str.begin(), str.end());

   l.sort();

   return string(l.begin(), l.end());

}

set<string> FindAnagrams(list<string>& dict, string findStr)

{

   map<string, set<string>> d;

   typedef pair<string, set<string>> MyPair;

   for(list<string>::const_iterator it = dict.begin(); it != dict.end(); ++it){

       string str(SortChars(*it));

       if(d.find(str) == d.end()){

           set<string> s;

           s.insert(*it);

           d.insert(MyPair(str, s));

       }

       else{

           d[str].insert(*it);

       }

   }

   string sortedStr(SortChars(findStr));

   return d[sortedStr];

}

int main(int argc, char* argv[])

{

   list<string> dict;

   dict.push_back("c");

   dict.push_back("car");

   dict.push_back("avt");

   dict.push_back("taac");

   dict.push_back("feet");

   dict.push_back("teef");

   dict.push_back("rom");

   dict.push_back("more");

   dict.push_back("pit");

   dict.sort();

   cout << "The dictionary: " << endl;

   copy(dict.begin(), dict.end(), ostream_iterator<string>(cout, ", "));

   cout << endl;

   list<string> testCases;

   testCases.push_back("d");

   testCases.push_back("car");

   testCases.push_back("rome");

   testCases.push_back("hell");

   testCases.push_back("");

   for(list<string>::iterator it = testCases.begin(); it != testCases.end(); ++it)

   {

       cout << endl << "Anagrams of " << *it << " in dictionary" << endl;

       set<string> output = FindAnagrams(dict, *it);

       copy(output.begin(), output.end(), ostream_iterator<string>(cout, ", "));

       cout << endl;

   }

   return 0;

}

8 0
3 years ago
Martina is responsible for the installation and maintenance of both hardware and software that make up her company’s network. Sh
natali 33 [55]

Answer:

The answer is "network administrator"

Explanation:

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  • She addresses issues that occur in everyday usage and work on long-term initiatives like as information backup or network maintenance.
5 0
4 years ago
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