<span>The problem is to calculate the angles of the triangle. However, it is not clear which angle you have to calculate, so we are going to calculate all of them
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we know that
Applying the law of cosines
c²=a²+b²-2*a*b*cos C------> cos C=[a²+b²-c²]/[2*a*b]
a=12.5
b=15
c=11
so
cos C=[a²+b²-c²]/[2*a*b]---> cos C=[12.5²+15²-11²]/[2*12.5*15]
cos C=0.694------------> C=arc cos (0.694)-----> C=46.05°-----> C=46.1°
applying the law of sines calculate angle B
15 sin B=11/sin 46.1-----> 15*sin 46.1=11*sin B----> sin B=15*sin 46.1/11
sin B=15*sin 46.1/11-----> sin B=0.9826----> B=arc sin (0.9826)
B=79.3°
calculate angle A
A+B+C=180------> A=180-B-C-----> A=180-79.3-46.1----> A=54.6°
the angles of the triangle are
A=54.6°
B=79.3°
C=46.1°
Do 3 Divided by 8 that will get u the decimal for the fraction
Answer:
31/2÷3/7
= 217
/6
= 36 1/6
≅ 36.16667
Step-by-step explanation:
Answer: 6
Step-by-step explanation:
the biggest number that can go into both 24 and 18 evenly is 6. 24/6 is four, and 18/6 is three
Answer:
0.436
Step-by-step explanation:
Given that a professor planned to give an examination in a large class on the Monday before Thanksgiving vacation
Some students asked whether he could change the date because so many of their classmates had at least one other exam on that date.
They speculated that at least 40% of the class had this problem.
The professor agreed to poll the class, and if there was convincing evidence that the proportion with at least one other exam on that date was greater than .40, he would change the date.
No of students in total = 250
Reported they had another exam = 109
proportion of the class reported that they had another exam on the date
=