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maksim [4K]
3 years ago
6

Factor each A.) x^3+7x^2+10x=0 B.) x^2 -6x+8=0

Mathematics
1 answer:
wel3 years ago
7 0
A) (X+5) (X+2)

B) (X-4) (X-2)
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Emma has 18 yellow flowers and 27 white flowers she wants to split them into vases in equal groupes what is the largest number o
wlad13 [49]
It’s 18

If they have to be equal, every vase has to have a yellow flower therefore if you had 1 yellow flower and 1 white flower (the lowest possible equal combination) then you can only have 18 groups otherwise you would have an equal number in each case
7 0
3 years ago
What is the slope-intercept form of 8x - y - 6 = 0?
Liula [17]
The slope intercept form is Y=mx + b
 8x - y - 6=0
<u>-8x          -8x
</u>-y= -6+8x = 0
     <u>+6        +6
</u>-y = 8x + 6
<u>
I hope you understand.

</u>
4 0
3 years ago
Read 2 more answers
HELP ASAAAAAP EXPLAIIINNN
kicyunya [14]

Answer:

dhdhrjfidgegehfr fhfn fhc fn dncc c. f byn

5 0
3 years ago
Read 2 more answers
Types of bonds are divided into three categories: good risk, medium risk, and poor risk. Assume that of a total of 11, 332 bonds
Alekssandra [29.7K]

Answer:

Probabilty of not poor= 0.75

Step-by-step explanation:

total of 11332 bonds.

7311 are good risk.

1182 are medium risk.

Poor risk

= total risk-(good risk+ medium risk)

= 11332-(7311+1182)

= 11332-8493

= 2839.

Poor risk = 2839

Probabilty that the ball choosen at random is not poor= 1 - probability that the ball is poor

Probability of poor = 2839/11332

Probabilty of poor= 0.2505

Probabilty that the ball choosen at random is not poor= 1- 0.2505

= 0.7495

To two decimal place= 0.75

3 0
3 years ago
A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute
Katyanochek1 [597]

Answer:

Step-by-step explanation:

Given that:

sample size n = 36

standard deviation = 10.1

level of significance ∝ = 0.10

The null hypothesis and the alternative hypothesis can be computed as follows:

H_0 : \sigma = 10

H_1 : \sigma \neq 10

The test statistics can be computed as follows:

X^2 = \dfrac{(n -1)s^2 }{\sigma ^2}

X^2 = \dfrac{(36 -1)10.1^2 }{10^2}

X^2 = \dfrac{(35)102.01 }{100}

X^2 = \dfrac{3570.35 }{100}

X^2 =35.704

degree of freedom = n - 1 = 36 - 1 = 35

Since this test is two tailed .

The P -value can be determined by using the EXCEL FUNCTION ( = 2 × CHIDIST(35.7035, 35)

P - value = 2 × 0.435163515

P - value = 0.8703      ( to four decimal places)

Decision Rule : To reject the null hypothesis if  P - value is less than the 0.10

Conclusion: We fail to reject null hypothesis ( accept null hypothesis) since p-value is greater than 0.10 and we conclude that there is sufficient claim that the normal range of pulse rates of adults given as 60 to 100 beats per minute resulted to a standard deviation of 10 beats per minute.

3 0
4 years ago
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