Factor each A.) x^3+7x^2+10x=0 B.) x^2 -6x+8=0

Penelope made note of all the bicycles and cars she could see parked or locked on acertain city block. All the cars had exactly

lesantik [10]

Given:

The number of cycles is, n (s) = 7.

The number of wheels in the cycle is, n (sw) = 2.

The number of cars is, n (c) = 15.

The number of wheels in the car is, n (cw) = 4.

The obective is to find the total number of wheels.

The total number of wheels is,

$\begin{gathered} T=n(sw)\cdot n(s)+n(cw)\cdot n(c) \\ =2\cdot7+4\cdot15 \\ =14+60 \\ =74\text{ whe}els \end{gathered}$

Hence, there are 74 wheels in the block.

If there are x bicycles and y cars, the equatioin will be,

$\begin{gathered} T=n(sw)\cdot x+n(ce)\cdot15 \\ T=2x+4x \end{gathered}$

Hence, the number of wheels for x bicycles and y cars is 2x+4x.

6 0

1 year ago

13. Given the following historical data and weights of .5, .3, and .2, what is the three-period weighted moving average forecast

Ostrovityanka [42]

Answer:

b. 144.8

Step-by-step explanation:

When calculating the moving average estimate of an observation , each of the observations are usually computed with the same weighted . In some cases, it is beneficial to assign different weight on the observations such that the observation closer to the time period being forecast, has higher weight. This is refer to as weighted moving average technique. The sum of the individual weight in a weighted moving average technique must equal to 1.

The three-period weighted moving average forecast for period 5 = 144*0.5 + 148 *0.3 + 142 *0.2 = 144.8

4 0

3 years ago

G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =

laiz [17]

Given:

The two functions are:

$g(b)=5b-9$

$h(b)=(b-1)^2$

To find:

The value of $(h\circ g)(-6)$ .

Solution:

We have,

$g(b)=5b-9$

$h(b)=(b-1)^2$

We know that,

$(h\circ g)(b)=h(g(b))$

$(h\circ g)(b)=h(5b-9)$

$(h\circ g)(b)=[(5b-9)-1]^2$

$(h\circ g)(b)=[5b-10]^2$

Putting $b=-6$ , we get

$(h\circ g)(-6)=[5(-6)-10]^2$

$(h\circ g)(-6)=[-39-10]^2$

$(h\circ g)(-6)=[-49]^2$

$(h\circ g)(-6)=2401$

Therefore, the value of $(h\circ g)(-6)$ is 2401.

7 0

3 years ago

Write an equation to represent each situation.

mina [271]

Answer:

18 years

Step-by-step explanation:

2(8+x) = 34+x

16+2x = 34+x

-18 = -x

4 0

3 years ago

A meter is 3.37 inches more than a yard swimmer a swims 100 meters and swimmer b swims 100 yeards how many more feet did swimmer

olga_2 [115]

Swimmer a swims 100 meters, which is 100 1-meters, which is 100
(1 yards +3.37 inches) = 100 yards + 337 inches.

1 yard is 3 feet, so 100 yards are 300 feet.

100 in is 8.33 feet so
337 in is (337*8.33)/100=28.07 feet

Swimmer b swims 100 yards, which is 300 feet

Swimmer a swam 28.07 feet.

4 0

3 years ago