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liubo4ka [24]
3 years ago
7

I WILL RATE YOU BRAINLIEST PLEASE HELP!!!!! I tried to put in .7 for the first one but that didn't work

Mathematics
1 answer:
drek231 [11]3 years ago
4 0
The answer is the answer is 0.7 not just .7
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Hellppp me outttt plzzzz
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Answer sorry i cant help u rn

Step-by-step explanation:

5 0
3 years ago
Which system of equations intersect at point A in this graph y = 10x - 1
scZoUnD [109]
Its the first one i think
8 0
3 years ago
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The answer choices are 11 1 2.48 6
Fudgin [204]

Answer:

The ball reached its maximum height of (11\ yards) in (1\ second).

Step-by-step explanation:

This question is essentially asking one to find the vertex of the parabola formed by the given equation. One could plot the equation, but it would be far more efficient to complete the square. Completing the square of an equation is a process by which a person converts the equation of a parabola from standard form to vertex form.

The first step in completing the square is to group the quadratic and linear term:

h(t)=-5t^2 + 10t + 6\\\\h(t) = (-5t^2 + 10t) + 6

Now factor out the coefficient of the quadratic term:

h(t)=-5(t^2 -2t) + 6

After doing so, add a constant such that the terms inside the parenthesis form a perfect square, don't forget to balance the equation by adding the inverse of the added constant term:

h(t) = -5(t^2 -2t) + 6\\\\h(t) = -5(t^2 -2t + 1 -1 ) + 6

Now take the balancing term out of the parenthesis:

\\\\h(t)=-5(t^2 -2t + 1) + 6 + ((-1)(-5))

Simplify:

h(t) = -5(t^2 -2t + 1) + 6 + 5\\\\h(t) = -5(t-1)^2 + 11

The x-coordinate of the vertex of the parabola is equal to the additive inverse of the numerical part of the quadratic term. The y-coordinate of the vertex is the constant term outside of the parenthesis. Thus, the vertex of the parabola is:

(1, 11)

8 0
3 years ago
Help please! I don't get this.​
slava [35]
Try using a photo scanner
8 0
3 years ago
Read 2 more answers
7 cos x+1=6 secx solve for x
jonny [76]
7cos(x) + 1 = 6sec(x)
7cos(x) + 1 = 6/cos(x)
7cos^(x) + cos(x) = 6
7cos^(x) + cos(x) - 6 = 0
[7cos(x) - 6][cos(x) + 1] = 0
cos(x) = 6/7 , x = arccos(6/7) and
cos(x) = -1, x = 180
6 0
3 years ago
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