For the first drawing, there are 30 tickets altogether, and Jason
has 10 of them. The probability that one of his tickets will win is
10 / 30 .
For the second drawing, there are 29 tickets altogether, and Jason
has 9 of them. The probability that one of his tickets will win is
9 / 29 .
For the third drawing, there are 28 tickets altogether, and Jason
has 8 of them. The probability that one of his tickets will win is
8 / 28 .
The probability that all three of these things will happen is
(10/30) x (9/29) x (8/28) = 720 / 24,360
= 6 / 203 = 2.96 percent (rounded)
Answer: 10x-6
Step-by-step explanation:
we know that perimeter P is 2L+2W
2L= 2(3x+2)=6x+4
2W=2(2x-5)=4x-10
P=6x+4+4x-10=10x-6
4 obviously lol
I answered this and I met my Challenge!
Answer:
20x-10
Step-by-step explanation:
Cows have
legs and 3 toes on each leg, if we want to find the number of toes of ONE cow we have to multiply the legs by the toes giving the following:

But we have two cows so (1) we have to multiply it by 2 giving a total of:

By the other hand chickens have
legs and 7 toes on each leg, if we want to find the number of toes we have to multiply the legs by the toes giving the following:

To find the total amount of toes we have to add (2) and (3)

The standard form of hyperbola is:
(x-h)²/a²-(y-k)²/b²=1
center:(4,5)
Length of the horizontal transverse axis: 8-5=3=2a
thus
a=3/2
a²=9/4
b=2
b²=4
Hence the equation will be:
(x-4)²/(9/4)-(y-5)²/4=1
simplifying this we get:
[4(x-4)²]/9-(y-5)²/4=1