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My name is Ann [436]
3 years ago
6

The hyperbola with center at (4, 5), with vertices at (0, 5) and (8, 5), with b = 2.

Mathematics
1 answer:
galina1969 [7]3 years ago
8 0
The standard form of hyperbola is:
(x-h)²/a²-(y-k)²/b²=1
center:(4,5)
Length of the horizontal transverse axis: 8-5=3=2a
thus
a=3/2
a²=9/4
b=2
b²=4

Hence the equation will be:
(x-4)²/(9/4)-(y-5)²/4=1
simplifying this we get:
[4(x-4)²]/9-(y-5)²/4=1
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Answer:

-13, -3

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Step-by-step explanation:

x, y are the numbers

x = 5y + 2

x×y = 39

(5y + 2)×y = 39

5y² + 2y - 39 = 0

the solution of a quadratic equation :

y = (-b ± sqrt(b² - 4ac))/2a

a = 5

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c = -39

y = (-2 ± sqrt(2² - 4×5×-39))/2×5 =

= (-2 ± sqrt(4 + 780))/10 =

= (-2 ± sqrt(784))/10 = (-2 ± 28)/10

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y2 = (-2 - 28)/10 = -30/10 = -3

x1 = 5×2.6 + 2 = 13 + 2 = 15

x2 = 5×-3 + 2 = -15 + 2 = -13

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