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My name is Ann [436]
3 years ago
6

The hyperbola with center at (4, 5), with vertices at (0, 5) and (8, 5), with b = 2.

Mathematics
1 answer:
galina1969 [7]3 years ago
8 0
The standard form of hyperbola is:
(x-h)²/a²-(y-k)²/b²=1
center:(4,5)
Length of the horizontal transverse axis: 8-5=3=2a
thus
a=3/2
a²=9/4
b=2
b²=4

Hence the equation will be:
(x-4)²/(9/4)-(y-5)²/4=1
simplifying this we get:
[4(x-4)²]/9-(y-5)²/4=1
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Step-by-step explanation:

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Answer:

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eliminate one variable by adding the equations

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serious [3.7K]

Answer:

m∠BAC = 105°

m∠FAB = 75°

Step-by-step explanation:

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From the triangle given in the picture,

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Since, ∠BAC and ∠FAB are the linear pair of angles,

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D: 1/6 * 2 = 2/12

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