Answer:
A) 0.303
The probability that a randomly selected student from the class has brown eyes , given they are male

Step-by-step explanation:
<u>Explanation</u>:-
Given data
Brown Blue Hazel Green
Females 13 4 6 9
Males 10 2 9 12
<em>Let 'B' be the event of brown eyes </em>
<em>Total number of males n(M) = 33</em>
Let B/M be the event of randomly selected student from the class has brown eyes given they are male
<em>The probability that a randomly selected student from the class has brown eyes , given they are male</em>
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<em>From table the brown eyes from males = 10</em>


<u>Final answer</u>:-
The probability that a randomly selected student from the class has brown eyes , given they are male

well, we know it's a line, and to get the equation of any line all we need is two points, let's pick two from the table hmmmm say let's use (-3 , -7) and (3 , 11)


Check the picture below
if that red segment, GJ, is parallel to the AE base segment of the triangle, then, the segment GJ is the midsegment of the triangle, and by the side-splitter theorem, those two triangles are similar.