Answer:
14/3
Step-by-step explanation:
Simplify the following:
48/6 - 10/3
Hint: | Reduce 48/6 to lowest terms. Start by finding the GCD of 48 and 6.
The gcd of 48 and 6 is 6, so 48/6 = (6×8)/(6×1) = 6/6×8 = 8:
8 - 10/3
Hint: | Put the fractions in 8 - 10/3 over a common denominator.
Put 8 - 10/3 over the common denominator 3. 8 - 10/3 = (3×8)/3 - 10/3:
(3×8)/3 - 10/3
Hint: | Multiply 3 and 8 together.
3×8 = 24:
24/3 - 10/3
Hint: | Subtract the fractions over a common denominator to a single fraction.
24/3 - 10/3 = (24 - 10)/3:
(24 - 10)/3
Hint: | Subtract 10 from 24.
| 2 | 4
- | 1 | 0
| 1 | 4:
Answer: 14/3
Answer:
approx 15.5 hours
Step-by-step explanation:
475/30 = 15.83 miles per hour
245 = 15.83·t
t = 245/15.83
t = 15.5 hours
Answer:
D is the correct answer
Step-by-step explanation:
first you subtract the 3 from the left side and add it to the right side. then you divide both side by negative 3 and flip the less than sign to a greater than sign
OK first let's check the x=1.5.





Oh my, that's called a depressed cubic, no

term. There's a formula for these very much like the quadratic formula but you're probably not quite old enough for that. Anyway,

is a solution, but that's not what they're asking. They are asking us to compare

with

and conclude

It turns out we did need all the rest of it. Save those brain cells, there's lots more math coming.
~~~~~~~~~~~~~~
I love it when the student asks for more. Here's the formula for a depressed cubic. I won't derive it here (though I did earlier today, coincidentally, but I'm probably not allowed to link to my Quora answer "what led to the discovery of complex numbers" from here). We use the trick of putting coefficients on the coefficients to avoid fractions.

has solutions
![x = \sqrt[3] { q - \sqrt{p^3 + q^2} } + \sqrt[3] {q + \sqrt{p^3 + q^2} } ](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%20%7B%20q%20-%20%5Csqrt%7Bp%5E3%20%2B%20q%5E2%7D%20%7D%20%2B%20%5Csqrt%5B3%5D%20%7Bq%20%2B%20%5Csqrt%7Bp%5E3%20%2B%20q%5E2%7D%20%7D%20%0A%0A)
That's pretty simple, though sometimes we end up having to take the cube roots of complex numbers, which isn't that helpful. Let's try it out on

That's
so
![x = \sqrt[3] { 3 - \sqrt{(2/3)^3+9} } + \sqrt[3] {3 + \sqrt{(2/3)^3+9} }](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%20%7B%203%20-%20%5Csqrt%7B%282%2F3%29%5E3%2B9%7D%20%7D%20%2B%20%5Csqrt%5B3%5D%20%7B3%20%2B%20%5Csqrt%7B%282%2F3%29%5E3%2B9%7D%20%7D%20)
![x = \sqrt[3] { 3 - \sqrt{753}/9 } +\sqrt[3]{3 + \sqrt{753}/9 }](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%20%7B%203%20-%20%5Csqrt%7B753%7D%2F9%20%7D%20%2B%5Csqrt%5B3%5D%7B3%20%2B%20%5Csqrt%7B753%7D%2F9%20%7D)
