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Nutka1998 [239]
4 years ago
15

All identities are equations, and all equations are identities. True of False

Mathematics
2 answers:
trasher [3.6K]4 years ago
8 0
All identities are equations, but ONLY SOME equations are identities.

sinx = cos(π/2 - x) (Equation and Identity

y= cosx -x², it's an equation but NOT an identity
Ganezh [65]4 years ago
7 0

Answer: false


Step-by-step explanation:


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Mademuasel [1]
You have to leave Y by itself in one side. To do that, you need to subtract 2x from both sides. You're now left with -3y = 8-2x. Last step is that you divide 3y, 8, and -2 by -3. 

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I need help on two questions!
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1) Answer: \frac{x^{2}}{100} +\frac{y^{2}}{4} = 1

<u>Explanation:</u>

The equation of an ellipse is: \frac{(x-h)^{2}}{a^{2}} +\frac{(y-k)^{2}}{b^{2}} = 1 ; where (h, k) is the center, "a" is the x-radius, and "b" is the y-radius.

               Center                        Radius

x-axis:   (10 + -10)/2 = 0            10 - 0 = 10

  •       h = 0                             a = 10

y-axis:   (2 + -2)/2  = 0               2 - 0 = 2

  •       k = 0                             b = 2

Now, input the values into the equation:

\frac{(x-0)^{2}}{10^{2}} +\frac{(y-0)^{2}}{2^{2}} = 1

\frac{x^{2}}{100} +\frac{y^{2}}{4} = 1

************************************************************************

2) Answer: \frac{x^{2}}{1} +\frac{(y+2)^{2}}{4} = 1

<u>Explanation:</u>

Vertices are: (0, 1) and (0, -5) ------> x-values are the same, y = 1, -5

Covertices are: (-1, -2) and (1, -2) ----> y-values are the same, x = -1, 1


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x-axis:   (-1 + 1)/2 = 0                  1 - 0 = 1

  •       h = 0                             a = 1

y-axis:   (1 + -5)/2  = -2               1 - (-2) = 3

  •       k = -2                             b = 3

Now, input the values into the equation:

\frac{(x-h)^{2}}{a^{2}} +\frac{(y-k)^{2}}{b^{2}} = 1

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vodka [1.7K]

Hello!

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Therefore, we have a 1/4 or 25% chance of tossing two heads in a row.

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